mysql - MYSQL - 根据条件更新新列的值

Question

我有下表

+--------------+------------+------+-----+---------+-------+
| Field        | Type       | Null | Key | Default | Extra |
+--------------+------------+------+-----+---------+-------+
| image_id     | int(11)    | YES  |     | NULL    |       |
| image_status | bit(3)     | YES  |     | NULL    |       |
| image_result | varchar(4) | YES  |     | NULL    |       |
+--------------+------------+------+-----+---------+-------+

image_id 和 image_status 列填充了值。image_result 中的值都是 NULL。

我想根据以下条件将以下值插入到 image_result 列中（我想更新表中的所有行）-

• 如果 image_status = '0' OR image_status = '3' 那么 image_result = 'Pass'
• 如果 image_status = '1' OR image_status = '4' 那么 image_result = 'Warn'
• 如果 image_status = '2' 那么 image_result = 'Fail'

我该怎么做以上？

Answer 1

UPDATE table 
SET image_result = CASE 
    WHEN image_status = 0 OR image_status = 3 THEN 'Pass' 
    WHEN image_status = 1 OR image_status = 4 THEN 'Warm' 
    ELSE 'Fail' 
END 

Answer 2

UPDATE TableName
SET image_result = CASE 
                     WHEN image_status = '0' OR image_status = '3' THEN 'PASS'  
                     WHEN image_status = '1' OR image_status = '4' THEN 'Warn' 
                     WHEN image_status = '2' THEN 'Fail'
                   END
WHERE image_status IN('0', '1', '2', '3', '4'); 

Answer 3

update <table> set image_result = 
Case when image_status = '0' OR image_status = '3' then 'Pass'
     when image_status = '1' OR image_status = '4' then 'Warn'
     when image_status = '2'                       then 'Fail'
End