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我被困在一个问题上。我试图在这个程序分配中找到测验的平均值。这是我的代码。粗体代码是我的问题所在。

 #include <stdlib.h>
 #include <stdio.h>
 #define STUDENTS 4
 #define QUIZZES 5

 main () {

int quizScores [STUDENTS] [QUIZZES] = {
    { 90, 90, 90, 90, 90 },
    { 90, 80, 70, 60, 50 },
    { 90, 89, 88, 87, 86 },
    { 90, 85, 80, 75, 70 }
 };
 int studentTotal = 0, quizTotal, row, col;
 double studentAverage, quizAverage;

 for ( row = 0; row < STUDENTS; row++) {
     studentTotal = 0;
     for ( col = 0; col < QUIZZES; col++) {
         studentTotal += quizScores[row][col];
     }
     studentAverage = (double) studentTotal / QUIZZES;
     printf("Student %i has average %.2lf\n", row, studentAverage);
 }

 **for ( col = 0; col < QUIZZES; col++) {
     quizTotal = 0;
     for ( row = 0; row < STUDENTS; row++) {
         quizTotal += quizScores[col][row];  
     }
     quizAverage = (double) quizTotal / STUDENTS;
     printf("Quiz %i has an average %.2lf\n",col, quizAverage);
     // output the average for this quiz
 }**

system("pause");
}
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1 回答 1

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您将索引混合在quizTotal += quizScores[col][row];. 应该是quizTotal += quizScores[row][col];

于 2012-10-09T03:50:35.323 回答