3 
./csf_install.sh: line 30: syntax error near unexpected token `CHECK_distro'
./csf_install.sh: line 30: `CHECK_distro()'

我的代码：

    if [ "$(whoami &2>/dev/null)" != "root" ] && [ "$(id -un &2>/dev/null)" != "root" ] ; then
        $BIN_ECHO " must be root to run this script "
        exit 1
    else
        $BIN_ECHO -e " permission check passed "
    fi
    CHECK_architecture()
    CHECK_distro()
...
CHECK_architecture()
{
    architecture=`uname -m`
    if [ "$architecture" != "x86_64" ] && [ "$architecture" != "ia64" ]; then
        architecture="x86"
    else
        architecture="x86_64"
    fi
}

CHECK_distro()
{
    DISTRO="";
    if [ `uname -r | egrep '(6.2-RELEASE|6.1-RELEASE|5.5-RELEASE|6.1-STABLE|5.4-RELEASE|6.0-RELEASE|5.3-RELEASE|4.10-RELEASE|4.11-RELEASE)'` ]; then
        DISTRO="FreeBSD";
        $BIN_ECHO " System is running FreeBSD"
    elif [ -f /etc/debian_version ];  then
           $BIN_ECHO " System is running Debian Linux"
           DISTRO=DEBIAN;
    elif [ -f /etc/SuSE-release ]; then
           $BIN_ECHO " System is running SuSE Linux"
           DISTRO=SUSE;
    elif [ -f /etc/fedora-release ]; then
           $BIN_ECHO " System is running Fedora Linux"
           DISTRO=FEDORA;
    elif [ -f /etc/redhat-release ]; then
           $BIN_ECHO " System is running Red Hat Linux"
           DISTRO=REDHAT;
    else
        $BIN_ECHO -e " no supported distribution found running "
    exit 1
fi
}

是不是我的校验码错了？或者是我如何做我的功能？功能需要放在第一位吗？

还

有没有更好的方法来检查和设置操作系统的分布？

4

2 回答 2

1

要调用函数，请不要使用()（您可以像调用任何其他 shell 命令一样调用它们）：

CHECK_architecture
CHECK_distro

您可能还希望在使用它们之前声明这些函数以避免任何麻烦。

于 2012-10-08T19:41:13.117 回答
1

调用函数时不要使用括号，并在调用函数之前定义函数。

例如：

foo() { # define foo; }
foo 1 2 3 # call foo with 3 arguments
于 2012-10-08T19:41:47.550 回答