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如何在球衣 POST 注释中访问 POST 方法(Android)发送的数据? 安卓客户端:

public class TestClient extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.layout_main);
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("myURL");

        try {

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
            nameValuePairs.add(new BasicNameValuePair("user", "user1"));
            nameValuePairs.add(new BasicNameValuePair("password", "password1"));
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            httpclient.execute(httppost);

        } catch (ClientProtocolException e) {

        } catch (IOException e) {

        }

    }

}

以下是Tomcat在Localhost上运行的Server的代码:

@Path("test")
public class Test {
     @GET
     @Produces(MediaType.TEXT_PLAIN)
        public String respondAsReady() {
            return "Running";
        }

     @POST
     @Consumes(MediaType.APPLICATION_FORM_URLENCODED)
     @Produces(MediaType.TEXT_PLAIN or other?)

              //Here I'd like the program to post (with System.out.println) the data to the console which is uploaded by the client using the POST method.


        }
}
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1 回答 1

1

无论客户端是使用 httpclient 的 PHP、html 还是 android,服务器端都不应该关心。您应该能够使用 @FormParam 注释来获取值。请参阅我在评论中发布的问题或此示例中的答案。

您应该能够将答案更改为更简单的内容,例如:

@POST
@Consumes(MediaType.APPLICATION_FORM_URLENCODED)
public void themethodname(@FormParam("user") String user, 
                          @FormParam("password") String password) {
    System.out.println("Username: "+user+", "+"Password: "+password);
}
于 2012-10-08T17:46:12.740 回答