3

我有一个名为 hibernate 的对象User，它与另一个名为Post. 这种关系被称为likedPosts（从User角度来看）。

<set name="likedPosts" lazy="true" table="Likes" where="Deleted=0">
        <cache usage="read-write"/>
        <key column="UserID"/>
        <many-to-many column="PostID" class="Post"/>
    </set>

目前我有一个简单的 HQL 查询来返回喜欢的帖子列表，如下所示：

"select user.likedPosts from User user where user.id=:uid"

我想要的是让这个列表按Post对象中的属性排序（特别是帖子 ID）。我（天真的）尝试这样做是这样的：

"select user.likedPosts from User user where user.id=:uid 
        order by user.likedPosts.id desc"

但这不起作用 - 我收到一个异常，告诉我我不允许这样做。我该怎么做呢？谢谢！

错误的堆栈跟踪：

org.hibernate.QueryException: illegal attempt to dereference collection [user0_.ID.likedPosts] with element property reference [id] [select user.likedPosts from com.pashash.domain.User user where user.id=:uid order by user.likedPosts.id desc]
    at org.hibernate.hql.ast.tree.DotNode$1.buildIllegalCollectionDereferenceException(DotNode.java:46)
    at org.hibernate.hql.ast.tree.DotNode.checkLhsIsNotCollection(DotNode.java:513)
    at org.hibernate.hql.ast.tree.DotNode.resolve(DotNode.java:221)
    at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:94)
    at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:90)
    at org.hibernate.hql.ast.HqlSqlWalker.resolve(HqlSqlWalker.java:728)
    ...
4

1 回答 1

6

你需要一个明确的加入来做到这一点：

select post from User user
inner join user.likedPosts post
where user.id = :userId
order by post.id desc
于 2012-10-08T12:22:28.547 回答