sql-server-2008 - 如何在 sql server 2008 中添加单列的时间（如 9:25:03 + 11:36:27 =）

Question

我有列（时间数据类型），其中包含类似的值

9:25:03 
4:43:21 
2:50:13 
11:25:33

，我应该写什么查询来获取列中所有值的总和

Answer 1

试试这个：

;with cte as(
select SUM(DATEPART(hh,tm))*3600+
       SUM(DATEPART(MI,tm))*60+
       SUM(DATEPART(SS,tm)) tme
from time_table)
SELECT cast(datepart(hh,cast(CONVERT(varchar(8),
       DATEADD(ss, tme  , 0), 114) as time))+
       datediff(dd,'1900-01-01',CONVERT(varchar, 
       DATEADD(ss, tme  , 0), 121))*24 as varchar(20))+
       right(CONVERT(varchar(8), DATEADD(ss, tme  , 0), 114),6)
from cte    

结果

28:24:10

SQL Fiddle 演示

Answer 2

把你的时间变成秒，然后把它们加起来。

with YourTable(TimeCol) as
(
  select '9:25:03' union all
  select '4:43:21' union all
  select '2:50:13' union all
  select '11:25:33'
)

select sum(datediff(second, 0, TimeCol)) sumSeconds
from YourTable

结果：

sumSeconds
-----------
102250

Answer 3

试试这个：

create table tbl123(tm time)

insert into tbl123
values('9:25:03'),('4:43:21'),('2:50:13'),('11:25:33')



;WITH CTE as(select SUM(DATEPART(hh,tm)) as hh,SUM(DATEPART(mi,tm)) as mm,SUM(DATEPART(ss,tm)) as ss from tbl123)

SELECT cast(hh+(mm+(ss/60))/60 as varchar(10))+':'+
       cast((((mm+(ss/60))%60)) as varchar(10))+':'+
       cast(ss%60 as varchar(10)) 
       from CTE

结果：

   28:24:10