php - 在类中包含字符串

Question

可能重复：
我如何在 php 类中包含 php 文件

我有一个这样开头的 PHP 文件：

<?php

include("strings.php");

class example {

strings.php 的格式如下

$txt['something'] = "something";
$txt['something_else'] = "something else";

我的问题是，如何$txt['something']在课堂上调用内部方法example？我知道$this->txt['something']不起作用

这可能是基本的东西，但我刚开始学习 PHP

Answer 1

Depends:

Do the entire (or most of the) object need the strings to work, or just a method or two?

• If yes, you should pass it in the constructor of the object:

  class Example {
      private $texts;
  
      public function __construct($texts) {
          $this->texts = $texts; //Now the array is available for all of the methods in the object, via $this->texts
      }
  }
  
  $example = new Example($txt);
  

• If not, you should pass it in to the relevant method which needs it.

  class Example {
      private $texts;
  
      public function method($texts) {
          //Do stuff with $texts
      }
  }
  
  $example = new Example;
  $example->method($txt);
  

Answer 2

An included file that just defines variables generally is a sign for bad design and definitely not OOP. But if you have to work with that, include the file from within the class and let it return the array:

class Example
{
    protected $txt;
    public function __construct($include = 'strings.php')
    {

        $this->txt = include($include);
    }
    public function someMethod()
    {
        return $this->txt['somestring'];
    }
}

Answer 3

Unless strings.php contains any more wrapping code $txt is a global variable. Php does not allow access to normal global variables from within functions and methods unless explicitly declared.

http://php.net/manual/en/language.variables.scope.php

You call it by first declaring it in the function

class MyClass{

public function MyMethod() {
{
    global $txt;
    echo $txt['fddf'];

This is a citation from php.net

<?php
$a = 1; /* global scope */ 

function test()
{ 
    echo $a; /* reference to local scope variable */ 
} 

test();
?>

This script will not produce any output because the echo statement refers to a local version of the $a variable