-2

我已经做了足够的研究，登录时它不会将我重定向到资源页面，以防密码正确。我之前尝试过密码的 SHA1，但首先处理更简单的情况，我删除了它。当我问 NAME = '$usr'，因为我有用户作为用户名，如果我也输入用户，它不会显示错误的用户名，如果我们尝试这个，在终端上，对于用户名 'user' 或 'User'，它显示一样。

<?php
    $con = mysql_connect("localhost","root","*****");
    session_start();
if(isset($_POST['submit1']))
    {
            if (!$con)
            {
                    die("OOPS!Could not connect to server".mysql_error());
            }
                    $passwd = $_POST['password'];
                    $usr=$_POST['username'];
                    mysql_select_db('USERS',$con) or die(mysql_error());
                    $result = mysql_query("SELECT PASSWD FROM USERS WHERE USERNAME='$usr'",$con) Or die(mysql_error());
                    $pass = mysql_result($result,0);
                    if ($pass==$passwd) {
                            header('Location : resource.html');}
                    else
                            {echo "sorry $usr wrong username or password"; }

    }
else if(isset($_POST['submit2']))
    {
            $usr = $_POST['user'];
            $passwd = $_POST['password1'];
            $name = $_POST['fullname'];
            mysql_select_db('USERS',$con) or die(mysql_error());
            $result = mysql_query("SELECT * FROM USERS WHERE USERNAME='$usr'",$con) Or die(mysql_error());
            $num = mysql_num_rows($result);
            if ($num==0) {
            mysql_query("INSERT INTO USERS(NAME,USERNAME,PASSWD) VALUES('$name','$usr','$passwd')");
            echo "congrats! you have been added.Go back to resources and log in";
            }
            else echo "Someone already has that username. Go back and try with another username";
    }

 mysql_close($con);
?>
4

1 回答 1

1

你在回声前少了一个分号

mysql_query("INSERT INTO USERS(NAME,USERNAME,PASSWD) VALUES('$name','$usr','$passwd')");//<-- right here
echo "congrats! you have been added.Go back to resources and log in";

另外，您没有清理用户输入，请查看准备好的语句（PDO，mysqli）

于 2012-10-06T18:49:46.183 回答