python - python：多个SocketServer同时工作

Question

我想在一个 python 程序中制作 3 个 SocketServer：

import threading
import SimpleHTTPServer
import SocketServer

class PolicyHandler(SocketServer.BaseRequestHandler):
    def handle(self):
        self.data = self.request.recv(128).strip()
        print self.data
        if self.data == '<policy-file-request/>\0':
            self.request.sendall('message 1')


class LiveRequestHandler(SocketServer.BaseRequestHandler):
    def handle(self):
        self.request.sendall('message 2')


def main():
    httpd = SocketServer.TCPServer(('',80),\
                               SimpleHTTPServer.SimpleHTTPRequestHandler)
    httpdThr = threading.Thread(target=httpd.serve_forever)
    httpdThr.daemon = True
    httpdThr.start()

    liveServer = SocketServer.TCPServer(('',8090), LiveRequestHandler)
    livThr = threading.Thread(target=liveServer.serve_forever)
    livThr.daemon = True
    livThr.start()

    policyServer = SocketServer.TCPServer(('',834), PolicyHandler)
    policyThr = threading.Thread(target=policyServer.serve_forever)
    policyThr.daemon = True
    policyThr.start()

if __name__ == '__main__':
    main()

我运行它，输出如下：

Finding files... done.
Importing test modules ... done.

----------------------------------------------------------------------
Ran 0 tests in 0.000s

OK

奇怪的是它立即退出程序，所以我的客户端程序无法连接到三套接字服务器。如何防止它退出程序？

Answer 1

If you really want to start the three servers from the same program, that would be one solution.

Answer 2

当没有更多非守护线程运行时，守护线程终止，因此它们在主线程结束时退出。添加一些内容以保持 main 运行，例如：

raw_input('Press enter to stop servers.')

Answer 3

现在我改变我的代码如下：

httpd = SocketServer.TCPServer(('',80), SimpleHTTPServer.SimpleHTTPRequestHandler)
httpdThr = threading.Thread(target=httpd.serve_forever)
httpdThr.daemon = True
httpdThr.start()

liveServer = SocketServer.TCPServer(('',8090), LiveRequestHandler)
livThr = threading.Thread(target=liveServer.serve_forever)
livThr.daemon = True
livThr.start()

policyServer = SocketServer.TCPServer(('',834), PolicyHandler)
policyThr = threading.Thread(target=policyServer.serve_forever)
policyThr.daemon = True
policyThr.start()

它工作正常。但现在我不知道如何在需要时向客户端发送消息。