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使用 Windows API Code PackCommonOpenFileDialog时,如何在不获取路径信息的情况下检索filenamea file(如)?mydoc.text

4

2 回答 2

3

用 C#?

string lcMyPath = GetPathFromSomewhere();
string lcMyFilename = Path.GetFileName(lcMyPath); 

//-- C:\myfile.txt -> myfile.txt.
Console.WriteLine(lcMyFilename);

Path.GetFileName (System.IO)

于 2012-10-05T20:55:07.040 回答
1

试试这个:http: //msdn.microsoft.com/en-us/library/system.io.path.getfilename.aspx

string fileName = @"C:\mydir\myfile.ext";
string path = @"C:\mydir\";
string result;

result = Path.GetFileName(fileName);
Console.WriteLine("GetFileName('{0}') returns '{1}'", 
    fileName, result);

result = Path.GetFileName(path);
Console.WriteLine("GetFileName('{0}') returns '{1}'", 
    path, result);

// This code produces output similar to the following: 
// 
// GetFileName('C:\mydir\myfile.ext') returns 'myfile.ext' 
// GetFileName('C:\mydir\') returns ''
于 2012-10-05T20:55:32.850 回答