0

我的 JSON 具有以下结构：

{
"<Person>k__BackingField" =     {
    "_email" = "name@domain.com";
    "_emailUpdate" = 1;
    "_firstName" = "First";
    "_lastName" = "Last";
};
"<SharedKey>k__BackingField" = "some-long-random-string";
}

我正在使用 restkit 作为这个人登录。它创建帖子，并正确获得该响应。我的映射设置如下：

+(void)ConfigureAPI
{
[super ConfigureAPI];
// Initialize RestKit
[RKObjectManager managerWithBaseURLString: @"www.api_root.com/";
Class<RKParser> parser = [[RKParserRegistry sharedRegistry] parserClassForMIMEType:@"application/json"];
[[RKParserRegistry sharedRegistry] setParserClass:parser forMIMEType:@"text/plain"];

RKObjectMapping *mapping;

// Person
mapping = [RKObjectMapping mappingForClass:[Person class]];
[mapping mapKeyPath:@"_email" toAttribute:@"email"];
[mapping mapKeyPath:@"_emailUpdate" toAttribute:@"emailUpdate"];
[mapping mapKeyPath:@"_firstName" toAttribute:@"firstName"];
[mapping mapKeyPath:@"_lastName" toAttribute:@"lastName"];
[[RKObjectManager sharedManager].mappingProvider setMapping:mapping forKeyPath:@"<Person>k__BackingField"];
}

当我运行应用程序并调用获取 JSON 响应的函数时，我收到以下错误：

Terminating app due to uncaught exception 'NSUnknownKeyException', reason: '[<__NSCFString 0x7b41800> valueForUndefinedKey:]: this class is not key value coding-compliant for the key <Person>k__BackingField.'

有人知道我为什么会得到这个吗？一切似乎都设置正确

编辑

如果有帮助，这就是我处理响应的方式：

    // when you get the response...
    request.onDidLoadResponse = ^(RKResponse *response){
        RKObjectMapper *mapper = [RKObjectMapper mapperWithObject:[response bodyAsString] mappingProvider:[RKObjectManager sharedManager].mappingProvider];

        Person *person = nil;
        RKObjectMappingResult *mappingResult = [mapper performMapping];
        person = [mappingResult asObject];
    };
4

1 回答 1

1

在将响应字符串传递给 RKObjectMapper 之前，您不会将响应字符串转换为 JSON 对象。您传入的响应的字符串值没有响应，valueForKey:这解释了您得到的异常。您可以轻松地将其转换为如下对象：

request.onDidLoadResponse = ^(RKResponse *response){

    NSError *error;
    id jsonObject = [response parsedBody:&error];

    if(error)
        NSLog(@"Error parsing JSON: %@", error.localizedDescription);
    else {
        RKObjectMapper *mapper = [RKObjectMapper mapperWithObject:jsonObject mappingProvider:[RKObjectManager sharedManager].mappingProvider];

        Person *person = nil;
        RKObjectMappingResult *mappingResult = [mapper performMapping];
        person = [mappingResult asObject];
    }
};
于 2012-10-11T16:05:49.233 回答