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我刚刚将 OpenJPA 从 1.2 版更新到 2.2 版，我的许多 JUnit 都失败了。其中大多数是因为 ManyToOne 关系改变了行为。假设我们有两个实体

package org.my;

import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.ManyToOne;

@Entity
public class Many {

    @ManyToOne(fetch = FetchType.LAZY, optional = false)
    private One one;

    public One getOne() {
        return one;
    }

    public void setOne(One one) {
        this.one = one;
    }

}

和

package org.my;

import java.util.List;

@Entity
public class One {
    @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "one")
    private List<Many> many;

    public List<Many> getMany() {
        return many;
    }

    public void setMany(List<Many> many) {
        this.many = many;
    }

}

当我创建一个对象并将其设置为多个列表时，比坚持和提交我得到一个像这样的异常

org.apache.openjpa.persistence.InvalidStateException: The field "one" of instance "org.my.Many@4d9cfefb" contained a null value; the metadata for this field specifies that nulls are illegal.

我以为 OpenJPA 猫会找到 One 对象并将其放入 Many.one 字段中，我错了吗？如果没有，我怎么能做到这一点？

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1 回答 1

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List of One对象中的每个Many对象都应先设置一个，然后再保存

于 2012-10-05T09:49:15.820 回答