所以我刚开始接触编程，我不得不说这是我做过的最有成就感但最令人沮丧的事情。我正在承担难度越来越大的项目，其中最近的项目涉及使用蒙特卡洛方法和大量循环。以下是目前完成的代码：
#include <iostream>
#include <cstdlib>
#include <cmath>
#include <string>
#include <ctime>
using namespace std;
int main ()
{
srand (time(0));
string operation;
cout << "Using the letters 'o', or 'q', please indicate if you would like to simulate once, or quit the program: " << endl;
cin >> operation;
string reservoir_name; // Creating variables for reservoir
double reservoir_capacity;
double outflow;
double inflow_min;
double inflow_max;
if (operation == "q")
{
cout << "Exiting program." << endl;
system ("pause");
return 0;
}
while (operation == "o") // Choose one or multiple simulations.
{
string reservoir_name; // Creating variables for reservoir function
double reservoir_capacity;
double inflow_min = 0;
double inflow_max = 0;
double inflow_range = inflow_min + inflow_max;
double inflow_difference = inflow_max - inflow_min;
double inflow_threshold = .9 * inflow_range/2; // Math for acceptable flow threshold.
cout << "What is the name of the reservoir?" << endl;
cin.ignore ();
getline (cin,reservoir_name); // Grab whole string for reservoir name.
cout << "What is the capacity of the reservoir in MAF (Millions of Acre Feet)?" << endl;
cin >> reservoir_capacity;
cout << "What is the minimum inflow?" << endl;
cin >> inflow_min;
cout << "What is the maximum inflow?" << endl;
cin >> inflow_max;
cout << "What is the required outflow?" << endl;
cin >> outflow;
inflow_range = inflow_min + inflow_max;
inflow_threshold = .9 * inflow_range/2;
cin.ignore ();
if (outflow > inflow_threshold) // Check for unacceptable outflow levels.
{
cout << "Warning! The outflow is over 90% of the average inflow. Simulation aborted. Returning to main menu." << endl;
}
else
{
const int number_simulations = 10;
double fill_level = 0;
int years = 1;
cout << "Running simulation." << endl;
for (int i = 1; i < number_simulations; i++) // Each year
{
for (years; fill_level < reservoir_capacity; years++ )
{
double r = rand() * 1.0 / RAND_MAX;
double x = inflow_min + inflow_range * r;// SHOULD be between minimum inflow and maximum inflow.
if (fill_level < 0)
{
fill_level = 0;
}
} // Simulate the change of water level.
cout << years << endl;
}
}
cout << "What would you like to do now?" << endl; // Saving for later. The menu re-prompt message and code.
cout << "Using the letters 'o', or 'q', please indicate if you would like to simulate once, or quit the program: " << endl;
cin >> operation;
}
system ("pause");
return 0;
}
所以我想我的主要问题是我遇到了关于在“运行模拟”下面设置 for 循环的问题的内部 for 循环从查询随机值中得出可接受结果范围内的随机数。有人告诉我，这个想法是使用蒙特卡洛方法，即
double r = rand() * 1.0 / RAND_MAX;
double x = inflow_min + inflow_range * r;// SHOULD be between minimum inflow and maximum inflow.
所以程序将为流入创建一个随机值。这个想法是内部 for 循环将继续运行，直到从 0 开始的水库的填充水平达到水库容量。模拟多少年的过程（内部for循环的每次迭代代表一年）要由fill_level模拟for循环的父for循环重复10次。
当我尝试运行您在此处看到的程序时，它会一直运行到“运行模拟”，然后它不会继续进行。是否有比我更有经验的人理解我在说什么并知道发生了什么？