java、GWT 和与 API 交互的新手。我有一个我希望是一个简单的问题。
我已使用以下 curl 命令成功与 REST API 交互：
curl -d "OPERATION_NAME=ADD_REQUEST&TECHNICIAN_KEY=xxxxxxxxxxx&INPUT_DATA=<?xml version=%221.0%22 encoding=%22utf-8%22?><Operation><Details><requester>Me</requester><subject>Test</subject><description>Testing curl input</description></Details></Operation>" http://xx.xx.xx.xx/sdpapi/request/
现在，从教程中，我有以下代码，我希望能像上面的 curl 命令一样向远程服务器发布请求。
我想弄清楚（谷歌不喜欢）我在发送 URL 时如何传递 OPERATION_NAME、TECHNICIAN_KEY 和 INPUT_DATA 参数。任何建议、教程等将不胜感激。
以下来自我的服务器端实现接口：
@Override
public String postToRemoteServer(String serviceUrl)
throws HelpDeskTestException {
try {
//dividing url into host: http://some.server
//path: a/path/in/it
//and parameters: this=that&those=others
int hostStart= serviceUrl.indexOf("//");
int pathStart= serviceUrl.substring(hostStart + 2).indexOf("/");
int parameterStart= serviceUrl.substring(hostStart + 2 + pathStart).indexOf("?");
final String serverHost= serviceUrl.substring(0, hostStart + pathStart + 2);
final String serverPath= serviceUrl.substring(hostStart + 3,
hostStart + pathStart + 2 + parameterStart);
final String serverParameters= serviceUrl.substring(hostStart + pathStart + 3 + parameterStart);
final URL url = new URL(serverHost);
final URLConnection connection= url.openConnection();
connection.setDoOutput(true);
final OutputStreamWriter out= new OutputStreamWriter(connection.getOutputStream());
final BufferedReader in= new BufferedReader(new InputStreamReader(
connection.getInputStream()));
out.write("POST " + serverPath + "\r\n");
out.write("Host: " + serverHost + "\r\n");
out.write("Accept-Encoding: identity\r\n");
out.write("Connection: close\r\n");
out.write("Content-Type: application/x-www-form-urlencoded\r\n");
out.write("Content-Length: " + serverParameters.length() + "\r\n\r\n" +
serverParameters + "\r\n");
String result = "";
String inputLine;
while ((inputLine=in.readLine()) != null) {
result+= inputLine;
}
in.close();
out.close();
return result;
} catch (final Exception e) {
throw new HelpDeskTestException();
}