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我进行了 MSSQL 查询,计算过去 30 天的总唯一 IP 地址和总 IP 记录。

SELECT count(IPAddress) AS totalPageHits, count(DISTINCT IPAddress) AS totalVisitors, count(DateTime)
FROM recordTable
WHERE DateTime > GETDATE()-30

现在我很难计算平均每日页面点击量和平均每日独立访问者。我尝试使用AVG,但它给了我一条错误消息,说“操作数数据类型 varchar 对 avg 运算符无效。”
任何帮助是极大的赞赏。

4

2 回答 2

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SELECT  AVG(HitCount) as AverageHits,
    AVG(UniqueHitCount) As AverageUniqueHits
FROM
(
SELECT  COUNT(IPAddress) as HitCount,
        COUNT(DISTINCT IPAddress) as UniqueHitCount,
        DATEDIFF(d, GETDATE(), DateTime) as Day
FROM tblHitCounter
WHERE DateTime > GETDATE() - 30
GROUP BY DATEDIFF(d, GETDATE(), DateTime)
) sub
于 2012-10-04T18:59:44.777 回答
2

您需要按天分组,然后取平均值:

select avg(totalPageHits) as avgDailyTotalPageHits,
       avg(totalVisitors) as avgDailyTotalVisitors
from (SELECT cast(DateTime as date) as thedate,
             count(IPAddress) AS totalPageHits,
             count(DISTINCT IPAddress) AS totalVisitors, count(DateTime) as cnt
      FROM recordTable
      WHERE DateTime > GETDATE()-30
      group by cast(DateTime as date)
     ) t
于 2012-10-04T18:46:10.903 回答