java - 使用扫描仪类的问题。System.out.println("请输入学生1的分数");后，跳过两个问题

Question

package findingthehighestscore;
import java.util.Scanner;

public class FindingTheHighestScore
{

public static void main(String[] args)
{
    Scanner kybd = new Scanner(System.in);
    // store students names  
    String student1;
    String student2;
    String student3;
    String tempStudent;

    // store students scores
    double score1;
    double score2;
    double score3;
    double tempScore;

    //Prompt user for input of each student and their score
    System.out.println("Please enter the name of Student 1");
    student1 = kybd.nextLine();

    System.out.println("Please enter the score of student 1");
    score1 = kybd.nextByte();

    System.out.println("Please enter the name of Student 2");
    student2 = kybd.nextLine();

    System.out.println("Please enter the score of student 2");
    score2 = kybd.nextByte();

    System.out.println("Please enter the name of Student 3");
    student3 = kybd.nextLine();

    System.out.println("Please enter the score of student 3");
    score3 = kybd.nextByte();

    //if score2 is greater then score1 then swap scores. Score 1 will be printed as highest score
    if(score2 > score1)
    {
       tempScore = score1;      
       score1 = score2;
       score2 = tempScore;           
       tempStudent = student1;           
       student1 = student2;          
       student2 = tempStudent;          
    }

     //if score3 is greater then score1 then swap scores.
    if(score3 > score1)
    {
       tempScore = score1;
       score1 = score3;          
       score3 = tempScore;           
       tempStudent = student1;           
       student1 = student3;           
       student3 = tempStudent;           
    }        
    System.out.print(student1 + " has the highest score of " + score1);       
}

}

Answer 1

代替 ：-

student1 = kybd.nextLine();

和： -

student1 = kybd.next();

nextLine()方法不会读取当前输入末尾的换行符。因此，换行符将在下一次调用时读取。scanner.nextByte()它读取的不是字节而是换行符。

所以，它基本上跳过下一行（因为它从上一个输入中读取换行符）并在下一行之后前进光标。所以，你的nextByte()方法只是被跳过了..

因此，要阅读换行符，您可以使用next()方法.. 这样，下一次迭代将没有任何内容可供阅读..