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我正在尝试在双向链表中使用自定义数据类型。我可以创建列表，但是当我尝试调用插入函数时，它会出错。是什么导致了这个错误？

主.cpp：

#include "command.h" //my custom class 
#include "doublyLinkedList.h"
int main(){

    //create a queue of jobs:
    doublyLinkedList<command>* queue = new doublyLinkedList<command>;

    //creating a new command:
    command *c = new command();
    c->createCommand();
    c->print();
    const command *d = new command(c->name, c->description, c->shellString);

    queue->insert(*d); //problem line
};

doubleLinkedList.h 的插入函数：

template <class Type>
void doublyLinkedList<Type>::insert(const Type& insertItem)
{
nodeType<Type> *current;      //pointer to traverse the list
nodeType<Type> *trailCurrent; //pointer just before current
nodeType<Type> *newNode;      //pointer to create a node
bool found;

newNode = new nodeType<Type>; //create the node
newNode->info = insertItem;  //store the new item in the node
newNode->next = NULL;
newNode->back = NULL;

if(first == NULL) //if the list is empty, newNode is 
                  //the only node
{
   first = newNode;
   last = newNode;
   count++;
}
else
{
    found = false;
    current = first;

    while (current != NULL && !found) //search the list
        if (current->info >= insertItem)
            found = true;
        else
        {
            trailCurrent = current;
            current = current->next;
        }

    if (current == first) //insert newNode before first
    {
        first->back = newNode;
        newNode->next = first;
        first = newNode;
        count++;
    }
    else
    {
          //insert newNode between trailCurrent and current
        if (current != NULL)
        {
            trailCurrent->next = newNode;
            newNode->back = trailCurrent;
            newNode->next = current;
            current->back = newNode;
        }
        else
        {
            trailCurrent->next = newNode;
            newNode->back = trailCurrent;
            last = newNode;
        }

        count++;
    }//end else
}//end else
}//end insert

该代码适用于整数和字符串，但不适用于“命令”类型。

错误：

In file included from main.cpp:2:0:
doublyLinkedList.h: In member function âvoid doublyLinkedList<Type>::insert(const Type&) [with Type = command]â:
main.cpp:34:18:   instantiated from here
doublyLinkedList.h:171:13: error: no match for âoperator>=â in âcurrent->nodeType<command>::info >= insertItemâ
doublyLinkedList.h:171:13: note: candidates are:
/usr/include/c++/4.6/bits/stl_pair.h:232:5: note: template<class _T1, class _T2> bool std::operator>=(const std::pair<_T1, _T2>&, const std::pair<_T1, _T2>&)
/usr/include/c++/4.6/bits/stl_iterator.h:315:5: note: template<class _Iterator> bool std::operator>=(const std::reverse_iterator<_Iterator>&, const std::reverse_iterator<_Iterator>&)
/usr/include/c++/4.6/bits/stl_iterator.h:365:5: note: template<class _IteratorL, class _IteratorR> bool std::operator>=(const std::reverse_iterator<_IteratorL>&, const std::reverse_iterator<_IteratorR>&)
/usr/include/c++/4.6/bits/basic_string.h:2621:5: note: template<class _CharT, class _Traits, class _Alloc> bool std::operator>=(const std::basic_string<_CharT, _Traits, _Alloc>&, const std::basic_string<_CharT, _Traits, _Alloc>&)
/usr/include/c++/4.6/bits/basic_string.h:2633:5: note: template<class _CharT, class _Traits, class _Alloc> bool std::operator>=(const std::basic_string<_CharT, _Traits, _Alloc>&, const _CharT*)
/usr/include/c++/4.6/bits/basic_string.h:2645:5: note: template<class _CharT, class _Traits, class _Alloc> bool std::operator>=(const _CharT*, const std::basic_string<_CharT, _Traits, _Alloc>&)
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1 回答 1

3

似乎您正在尝试保持列表排序，但是您还没有为command. operator>=如果您想按原样使用它，您需要为您的类型实现。

它的签名可能看起来像这样：

bool operator>= (const command& a, const command& b);
于 2012-10-02T22:12:34.400 回答