mnth = DateDiff(DateInterval.Month, 8/30/2012, 10/1/2012)
给 mnth = 2
. 但是当我们看时,这些日期之间只有 32 天。我期待一个结果mnth=1
,因为这几天之间只有 32 天。
请帮忙..
在我的情况下,我可以将 15 天以上视为一个月,但如果小于 15 天,则不应考虑。
mnth = DateDiff(DateInterval.Month, 8/30/2012, 10/1/2012)
给 mnth = 2
. 但是当我们看时,这些日期之间只有 32 天。我期待一个结果mnth=1
,因为这几天之间只有 32 天。
请帮忙..
在我的情况下,我可以将 15 天以上视为一个月,但如果小于 15 天,则不应考虑。
要获得完整的月数,您可以根据您的解释做不同的事情,
Public Function CompleteMonthsBetweenA( _
ByVal start As DateTime, _
ByVal end As DateTime) As Integer
Dim invertor = 1
If (start > end) Then
Dim tmp = end
end = start
start = tmp
invertor = -1
End If
Dim diff = ((end.Year - start.Year) * 12) + end.Month - start.Month
If start.Day > end.Day Then
Return (diff - 1) * invertor
Else
Return diff * invertor
End If
End Function
使用此函数,2011 年 5 月 31 日 (dd/mm/yy) 和 2011 年 6 月 30 日之间的完整月数为 0,但 2011 年 6 月 6 日至 2011 年 7 月 31 日之间的完整月数为 1。这可能是也可能不是成为你所期望的。
Public Function CompleteMonthsBetweenB( _
ByVal start As DateTime, _
ByVal end As DateTime) As Integer
Dim invertor = 1
If (start > end) Then
Dim tmp = end
end = start
start = tmp
invertor = -1
End If
Dim diff = ((end.Year - start.Year) * 12) + end.Month - start.Month
Dim startDaysInMonth = DateTime.DaysInMonth(start.Year, start.Month)
Dim endDaysInMonth = DateTime.DaysInMonth(end.Year, end.Month)
If (start.Day / startDaysInMonth) > (end.Day / endDaysInMonth) Then
Return (diff - 1) * invertor
Else
Return diff * invertor
End If
End Function
使用此功能可以计算比率Day / DaysInMonth
,以便评估两个月的相对完成情况。
Public Function CompleteMonthsBetweenC( _
ByVal start As DateTime, _
ByVal enddate As DateTime) As Integer
Dim invertor = 1
If (start > enddate) Then
Dim tmp = enddate
enddate = start
start = tmp
invertor = -1
End If
Dim diff = ((enddate.Year - start.Year) * 12) + enddate.Month - start.Month
Dim remainingDays = _
(DateTime.DaysInMonth(start.Year, start.Month) - start.Day) + enddate.Day
If remainingDays < 15 Then
Return (diff - 1) * invertor
Else
Return diff * invertor
End If
End Function
此函数仅在剩余天数小于魔术数字 15 时向下舍入,我认为这是您在更新中所要求的。
Public Function CompleteMonthsBetweenD( _
ByVal start As DateTime, _
ByVal end As DateTime) As Integer
Return end.Subtract(start).TotalDays \ 30.436875
End Function
此函数采用更简单的方法,将总天数除以公历中每月的平均天数。
计算月差时不考虑日期的日部分。
例如,8/31/2012
和之间的月差9/1/2012
为 1,尽管这两个日期之间只有一天。
如果您想考虑日组件,您必须以天而不是月为单位获取日期差异,并计算您想要的月数。
这是我使用的类(它是 C#,但很容易转换为 VB.NET)。它适用于年、月、日……非常适合以#Y-#M-#D 格式显示年龄。
public class DateDifference
{
/// <summary>
/// defining Number of days in month; index 0=> january and 11=> December
/// february contain either 28 or 29 days, that's why here value is -1
/// which wil be calculate later.
/// </summary>
private int[] monthDay = new int[12] { 31, -1, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
/// <summary>
/// contain from date
/// </summary>
private DateTime fromDate;
/// <summary>
/// contain To Date
/// </summary>
private DateTime toDate;
/// <summary>
/// this three variable for output representation..
/// </summary>
private int year;
private int month;
private int day;
public DateDifference(DateTime d1, DateTime d2)
{
int increment;
if (d1 > d2)
{
this.fromDate = d2;
this.toDate = d1;
}
else
{
this.fromDate = d1;
this.toDate = d2;
}
///
/// Day Calculation
///
increment = 0;
if (this.fromDate.Day > this.toDate.Day)
{
increment = this.monthDay[this.fromDate.Month - 1];
}
/// if it is february month
/// if it's to day is less then from day
if (increment == -1)
{
if (DateTime.IsLeapYear(this.fromDate.Year))
{
// leap year february contain 29 days
increment = 29;
}
else
{
increment = 28;
}
}
if (increment != 0)
{
day = (this.toDate.Day + increment) - this.fromDate.Day;
increment = 1;
}
else
{
day = this.toDate.Day - this.fromDate.Day;
}
///
///month calculation
///
if ((this.fromDate.Month + increment) > this.toDate.Month)
{
this.month = (this.toDate.Month + 12) - (this.fromDate.Month + increment);
increment = 1;
}
else
{
this.month = (this.toDate.Month) - (this.fromDate.Month + increment);
increment = 0;
}
///
/// year calculation
///
this.year = this.toDate.Year - (this.fromDate.Year + increment);
}
public override string ToString()
{
//return base.ToString();
return this.year + " Year(s), " + this.month + " month(s), " + this.day + " day(s)";
}
public int Years
{
get
{
return this.year;
}
}
public int Months
{
get
{
return this.month;
}
}
public int Days
{
get
{
return this.day;
}
}
}
用法:
DateDifference diff = new DateDifference(date1, date2);
int months = (diff.Years*12) + diff.Months + diff.Days > 15 ? 1 : 0;
如果您想要完整月份的数量,那么您需要比较从壁橱月份开始的日期。
Sub Main()
' mnth = DateDiff(DateInterval.Month, 8/30/2012, 10/1/2012)
Console.WriteLine(GetCompleteMonthCount(New DateTime(2012, 8, 30), New DateTime(2012, 10, 1)))
Console.ReadLine()
End Sub
Public Function GetCompleteMonthCount(ByVal d1 As DateTime, ByVal d2 As DateTime) As Integer
If d1.Day <> 1 Then
d1 = d1.AddMonths(1)
d1 = New DateTime(d1.Year, d1.Month, 1)
End If
If d2.Day <> 1 Then
d2 = New DateTime(d2.Year, d2.Month, 1)
End If
Return DateDiff(DateInterval.Month, d1, d2)
End Function
上面的解决方案都很好,但可能有点过于复杂,怎么样
Function wholeMonthsEd(d1, d2) As Integer
' determine the DateDiff function output
' which gives calendar month difference
initMonths = DateDiff("m", d1, d2)
' do calcs on the Day of the month to deduct/not a calendar month
If Day(d2) < Day(d1) Then
initMonths = initMonths - 1
End If
wholeMonths = initMonths
End Function