CREATE TABLE TestTable (id int IDENTITY (1,1), name nvarchar(100));
INSERT INTO TestTable(name) VALUES ('data1');
INSERT INTO TestTable(name) VALUES ('data2');
Declare @Identity as int
set @identity=IDENT_CURRENT ('TestTable')
SET IDENTITY_INSERT TestTable ON;
我怎样才能实现这个功能?
INSERT INTO TestTable
Select * from
(
Select 55 as a,'data55' as b
Union
Select 56 as a,'data55' as b
)n
当它被替换时.. Msg 8101, Level 16, State 1, Line 7 只有在使用列列表并且 IDENTITY_INSERT 为 ON 时,才能为表“TestTable”中的标识列指定显式值。
INSERT INTO TestTable (id, name) VALUES (55, 'data55');
INSERT INTO TestTable (id, name) VALUES (56, 'data55');
SET IDENTITY_INSERT TestTable OFF;
DBCC CHECKIDENT (TestTable, reseed,@identity )
INSERT INTO TestTable(name) VALUES ('data3');
Select * from TestTable
Drop table TestTable