我想在一个过程中使用 Date_add 2 次,但它返回 0 行(而它应该返回行)
这是程序
select av.*, ap.*,c.* from tbl_available av
left join tbl_appointment ap on av.avHours = ap.appointmenttime
and ap.calendarid = kalenderId
and ap.appointmentdate = DATE_ADD(dag, INTERVAL 6 DAY)
left join tbl_client c on ap.clientid = c.clientid
where av.avCalendarId = KalenderId
and av.avDays = DayOfweek(DATE_ADD(dag, INTERVAL 6 DAY))
order by avHours;
它可以在没有 date_add 的情况下工作
提前致谢!
//编辑
我现在拥有的:
select av.*, ap.*,c.*, ab.absentid from tbl_available av
left join tbl_appointment ap on av.avHours = ap.appointmenttime
and ap.calendarid = kalenderId
and ap.appointmentdate BETWEEN dag AND DATE_ADD(dag, INTERVAL 6 DAY)
and (av.avDays = DayOfweek(ap.appointmentdate) OR ap.appointmentdate IS NULL)
left join tbl_client c on ap.clientid = c.clientid
left join tbl_absent ab on av.avHours = ab.ababsent
and ab.abHoliday = dag
and ab.abCalendarID = kalenderId
where av.avCalendarId = kalenderId
order by avDays,avHours;
但是没有获取 ab.absentid,这是为什么呢?:(