2

我有一个家庭作业...代码如下...有几个问题...在此先感谢。初学者Java学生...如果这看起来很笨拙，请不要笑>。>下面的代码...

    /*
     * Getting to know you...
     * @author Elle dela Victoria
     * @version 092812
     */
       import java.util.*;
       public class A15_1
       {
           public static void main(String[] args)
           {
           Scanner input = new Scanner(System.in);

           System.out.print(
           "Mind answering some questions for me?\n" +
           "Type quit when you're ready to leave.\n");

       while(true)
       {
        System.out.print("Does your name start with the letter H? ");
        input.nextLine();
        int ans = (int)(Math.random() * 5);
        if (ans == 0)
            System.out.println("That's awesome!");
        if (ans == 1)
            System.out.println("Awww, how unfortunate!");
        if (ans == 2)
            System.out.println("You're amazing at this!");
        if (ans == 3)
            System.out.println("LOL!");
        if (ans == 4)
            System.out.println("WTF!! That's horrible!");

        System.out.print("Are you male? ");
        input.nextLine();
        int ans1 = (int)(Math.random() * 5);
        if (ans1 == 0)
            System.out.println("That's awesome!");
        if (ans1 == 1)
            System.out.println("Awww, how unfortunate!");
        if (ans1 == 2)
            System.out.println("You're amazing at this!");
        if (ans1 == 3)
            System.out.println("LOL!");
        if (ans1 == 4)
            System.out.println("WTF!! That's horrible!");

        System.out.print("Are you female?");
        input.nextLine();
        int ans2 = (int)(Math.random() * 5);
        if (ans2 == 0)
            System.out.println("That's awesome!");
        if (ans2 == 1)
            System.out.println("Awww, how unfortunate!");
        if (ans2 == 2)
            System.out.println("You're amazing at this!");
        if (ans2 == 3)
            System.out.println("LOL!");
        if (ans2 == 4)
            System.out.println("WTF!! That's horrible!");

        System.out.print("Are you in school right now?");
        input.nextLine();
        int ans3 = (int)(Math.random() * 5);
        if (ans3 == 0)
            System.out.println("So angry when you're sober!");
        if (ans3 == 1)
            System.out.println("Awww, how unfortunate!");
        if (ans3 == 2)
            System.out.println("You're amazing at this!");
        if (ans3 == 3)
            System.out.println("LOL!");
        if (ans3 == 4)
            System.out.println("WTF!! That's horrible!");

        String userinput = input.nextLine();
        if (userinput.equalsIgnoreCase("quit"))
            break;      
      }
   }
 }
  1. 有什么方法可以对我提出的每个问题使用我的 IF 语句，而不必更改每个问题的字符串名称？
  2. 有没有办法为那些 if 语句创建一个方法（？），所以我不必为我问的每个问题都写出来？
  3. 如果用户在 10 秒内没有输入答案，我想要一个计时器来提示他们输入答案，我该怎么做？
4

4 回答 4

1

您可以拥有一个字符串数组并根据输入打印它们ans：

    String str[] = {"That's awesome!", "Awww, how unfortunate!",
     "You're amazing at this!", "LOL!", "WTF!! That's horrible!"};

      /* code */

  while(true)
       {
        System.out.print("Does your name start with the letter H? ");
        input.nextLine();
        int ans = (int)(Math.random() * str.length);
        System.out.println(str[ans]);

      /* code */
   }
于 2012-09-30T18:39:53.743 回答
0

我不确定这是否回答 1，但它应该回答 2：

private String getAnswer() {
   int ans = (int)(Math.random() * 5);
   switch(ans) {
   case 0:
      return "That's awesome!";
   case 1:
      return "Awww, how unfortunate!";
   [... and so on ...]
   }
   return null
}

不仅仅是在您需要这样的答案的地方调用它：System.out.println(getAnswer());

于 2012-09-30T18:42:38.410 回答
0

我建议使用列表来存储响应。这将减少对if语句的需求，并且还可以防止您必须在四个不同的地方添加新的响应。

List<String> responseList = new ArrayList<String>();
responseList.add("That's awesome!");
responseList.add("LOL!");
responseList.add(.....);

System.out.println(responseList.get(ans));
于 2012-09-30T18:44:42.147 回答
0

  1. 是的你可以。您创建一个带有int要使用的参数类型的方法：

    public void printReply(int ans) {
    if (ans == 0)
        System.out.println("So angry when you're sober!");
    if (ans == 1)
        System.out.println("Awww, how unfortunate!");
    if (ans == 2)
        System.out.println("You're amazing at this!");
    if (ans == 3)
        System.out.println("LOL!");
    if (ans == 4)
        System.out.println("WTF!! That's horrible!");
}

    在适当的地方调用它。

  2. 不确定我是否理解，我认为第一个答案涵盖了这一点。

  3. 查看wait()方法，该方法由所有Objects 指定。

顺便说一句，你没有对你的输入做任何事情。你打电话让它掉在地上input.nextLine()。您应该考虑在变量中捕获它。

于 2012-09-30T18:39:46.947 回答