2

在 Python 的标准max函数中，我可以传入一个key参数：

s = numpy.array(['one','two','three'])
max(s) # 'two' (lexicographically last)
max(s, key=len) # 'three' (longest string)

对于更大的（多维）数组，我们不能再使用max，但我们可以使用numpy.amax... 不幸的是，它没有提供key参数。

t = numpy.array([['one','two','three'],
                 ['four','five','six']], 
                dtype='object')
numpy.amax(t) # 'two` (max of the flat array)
numpy.amax(t, axis=1) # array([two, six], dtype=object) (max of first row, followed by max of second row)

我想要做的是：

amax2(t, key=len) # 'three'
amax2(t, key=len, axis=1) # array([three, four], dtype=object)

有没有内置的方法可以做到这一点？

注意：在第一次尝试写这个问题时，我无法amax在这个玩具示例中工作！

4

1 回答 1

0

这是一种非内置方式（它缺少使用时的功能out和keepdim参数），看起来相当长：amaxkey

def amax2(x, *args, **kwargs):
    if 'key' not in kwargs:
        return numpy.amax(x,*args,**kwargs)
    else:
        key = kwargs.pop('key') # e.g. len, pop so no TypeError: unexpected keyword
        x_key = numpy.vectorize(key)(x) # apply key to x element-wise
        axis = kwargs.get('axis') # either None or axis is set in kwargs
        if len(args)>=2: # axis is set in args
            axis = args[1]

        # The following is kept verbose, but could be made more efficient/shorter    
        if axis is None: # max of flattened
            max_flat_index = numpy.argmax(x_key, axis=axis)
            max_tuple_index = numpy.unravel_index(max_flat_index, x.shape)
            return x[max_tuple_index]
        elif axis == 0: # max in each column
            max_indices = numpy.argmax(x_key, axis=axis)
            return numpy.array(
                 [ x[max_i, i] # reorder for col
                     for i, max_i in enumerate(max_indices) ], 
                 dtype=x.dtype)
        elif axis == 1: # max in each row
            max_indices = numpy.argmax(x_key, axis=axis)
            return numpy.array(
                 [ x[i, max_i]
                     for i, max_i in enumerate(max_indices) ],
                 dtype=x.dtype)

此功能的想法是从@PeterSobot对我之前的问题的回答的第二部分扩展而来的。

于 2012-09-29T18:53:49.240 回答