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我有一个显示用户活动的 JSF 表。

<p:lineChart id="logins" value="#{StatisticsController.weekActivity}" legendPosition="e"  
                                 title="Weekly Logins" seriesColors="4D94FF, 1975FF, 005CE6, 0047B2" minY="0" maxY="200"/>


public class Statistics implements Serializable {

    private CartesianChartModel weeksActivity;

    public Statistics() {  
        createweeksActivity(); 

    }  

    public CartesianChartModel getweekActivity() {  
        return weeksActivity;  
    }

    private void createweeksActivity() {  
        weeksActivity = new CartesianChartModel();  

        ChartSeries boys = new ChartSeries();  
        boys.setLabel("Active Accounts");  

        boys.set("Monday", 120);  
        boys.set("Tuesday", 100);  
        boys.set("Wednesday", 44);  
        boys.set("Thursday", 150);  
        boys.set("Friday", 120);
        boys.set("Saturday", 82);  
        boys.set("Sunday", 115);  

        ChartSeries girls = new ChartSeries();  
        girls.setLabel("Blocked Accounts");  

        girls.set("Monday", 52);  
        girls.set("Tuesday", 60);  
        girls.set("Wednesday", 110);  
        girls.set("Thursday", 135);  
        girls.set("Friday", 120);
        girls.set("Saturday", 140);  
        girls.set("Saturday", 130);  
        girls.set("Sunday", 140);  

        weeksActivity.addSeries(boys);  
        weeksActivity.addSeries(girls);  
    }  


}

我想按顺序显示当前日期。例如：现在我得到这个订单：Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday 例如今天是星期三我想在打开网页时得到这个订单：

Thursday, Friday, Saturday, Sunday, Monday, Tuesday, Wednesday

我该如何解决这个问题？

EDIT:

我以这种方式更新了代码：

private void createweeksActivity()
    {

        weeksActivity = new CartesianChartModel();

        ChartSeries activeAccounts = new ChartSeries();
        activeAccounts.setLabel("Active Accounts");

        ChartSeries blockedAccounts = new ChartSeries();
        blockedAccounts.setLabel("Blocked Accounts");

        GregorianCalendar calendar = new GregorianCalendar();
        DateFormat df = new SimpleDateFormat("EEEE");
        for (int i = 0; i < 7; i++)
        {
            calendar.add(Calendar.DATE, 1);
            System.out.println(df.format(calendar.getTime()));
            activeAccounts.set(df.format(calendar.getTime()), getNumberOfLogins(df.format(calendar.getTime())));
            blockedAccounts.set(df.format(calendar.getTime()), getNumberOfLogins(df.format(calendar.getTime())));
        }       

        weeksActivity.addSeries(activeAccounts);
        weeksActivity.addSeries(blockedAccounts);
    }

    public int getNumberOfLogins(String day){

        // Get here the number of logins using SQL command
        // Example: SELECT * FROM HISTORY WHERE DAY = day;

        return 100;
    }

我想它会起作用的。

4

2 回答 2

5 
GregorianCalendar calendar = new GregorianCalendar();
DateFormat df = new SimpleDateFormat("EEEE");
for (int i = 0; i < 7; i++) {
    calendar.add(Calendar.DATE, 1);
    System.out.println(df.format(calendar.getTime()));
}

GregorianCalendar 在我们的公历下代表时间的瞬间。它的无参数构造函数将其初始化为当前时间。

DateFormat 用于格式化日期。您可以使用其方法将 a(Gregorian)Calendar转换为 Date 。getTime()“EEEE”是指一周中最长的一天。

该(Gregorian)Calendar.add()方法允许将值添加到日历的任何字段（年、月、日期、小时等）。由于您要遍历一周中的几天，因此我从明天开始，并在每次迭代时添加 1 天。

一切都在javadoc中可用。

于 2012-09-29T18:09:25.090 回答
1

根据日历，将您的星期几作为其星期数的地图。

然后使用 Calendar 获取当前日期并使用 Modular Arithmetic 更改排序。

就像是：

//This you can do it one time and then use it in your program
Map<Integer, String> daysOfWeek = new HashMap<Integer,String>();
daysOfWeek.put(Calendar.MONDAY, "Monday");
daysOfWeek.put(Calendar.TUESDAY, "Tuesday");
//so on and so forth.



//Now the code that will be running 
//You get your current Day  (Which will be the last one you want to see)
int weekday = calendar.get(Calendar.DAY_OF_WEEK);

//Start with next value (modulus 7 since you don't want overflow)
int currDay = (weekday+1) % 7;


//Go over the seven Days
for(int i = 0; i < 7; i++) {
    String currDay = daysOfWeek.get(currDay);  //Get your Day String

    //Here do whatever you need to do to set up the DAY in JSF

    currDay = (currDay+1) % 7;  //Moving currDay to the next Day
 }
于 2012-09-29T18:09:23.040 回答