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使用应用程序引擎的搜索 API，我尝试搜索包含,、=、(等的查询。它返回以下错误：

Failed to parse query "engines (Modular)"
Traceback (most recent call last):
  File "/base/python27_runtime/python27_lib/versions/third_party/webapp2-2.3/webapp2.py", line 1505, in __call__
  rv = self.router.dispatch(request, response)
File "/base/python27_runtime/python27_lib/versions/third_party/webapp2-2.3/webapp2.py", line 1253, in default_dispatcher
  return route.handler_adapter(request, response)
File "/base/python27_runtime/python27_lib/versions/third_party/webapp2-2.3/webapp2.py", line 1077, in __call__
  return handler.dispatch()
File "/base/python27_runtime/python27_lib/versions/third_party/webapp2-2.3/webapp2.py", line 547, in dispatch
  return self.handle_exception(e, self.app.debug)
File "/base/python27_runtime/python27_lib/versions/third_party/webapp2-2.3/webapp2.py", line 545, in dispatch
  return method(*args, **kwargs)
File "/base/data/home/apps/s~generatestock/12.362076640167792770/search.py", line 1641, in get
  result = find_search_document(search_item)
File "/base/data/home/apps/s~generatestock/12.362076640167792770/search.py", line 177, in find_search_document
  return search.Index(name=_INDEX_NAME).search(query)
File "/base/python27_runtime/python27_lib/versions/1/google/appengine/api/search/search.py", line 2715, in search
  query = Query(query_string=query)
File "/base/python27_runtime/python27_lib/versions/1/google/appengine/api/search/search.py", line 2286, in __init__
_CheckQuery(self._query_string)
File "/base/python27_runtime/python27_lib/versions/1/google/appengine/api/search/search.py", line 1964, in _CheckQuery
  raise QueryError('Failed to parse query "%s"' % query)

QueryError: Failed to parse query "Engines (Modular)"

为什么？搜索 API 是否支持这些字符？

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1 回答 1

7

要解析短语，请在短语周围使用引号：

query = '"Engines (Modular)"'
search.Index(name=_INDEX_NAME).search(query)

您可以简单地在现有查询周围加上引号：

query = '"{0}"'.format(query)
search.Index(name=_INDEX_NAME).search(query)

但是您可能必须删除查询中的现有引号才能使其正常工作。Google 的文档没有说明如何在搜索查询中包含引号。因此，完整的故障安全方法将是：

query = '"{0}"'.format(query.replace('"', ''))
search.Index(name=_INDEX_NAME).search(query)
于 2012-09-29T13:48:33.807 回答