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我是 android 开发方面的新手，我知道我想尝试的一件事是如何使用 HTTP Get。我已经设置了整个方法，以便发送文本并且我的结果以字符串形式返回，但我想知道的是如何获取该字符串并仅提取我真正需要的部分。例如字符串回来了

{"id":"124343","name":"somename" }

如果我只是想获得该开始的 id 部分，我将如何在 android 中做到这一点。我正在搜索文档，但到目前为止我还没有真正找到任何东西，然后我发现的大部分内容也都围绕着使用 JSON。

下面是我目前正在使用的代码（我已经从几个不同的帖子一起编译）但也许我需要切换到使用 JSON 进行解析，我只是不确定在哪里进行更改

     //This class is called after a button is pressed and the HTTPGet string is compiled from text within a textview and a static string (this already works)
     private class LongRunningGetIO extends AsyncTask<Void, Void, String> {
    protected String getASCIIContentFromEntity(HttpEntity entity)
            throws IllegalStateException, IOException {
        InputStream in = entity.getContent();
        StringBuffer out = new StringBuffer();
        int n = 1;
        while (n > 0) {
            byte[] b = new byte[4096];
            n = in.read(b);
            if (n > 0)
                out.append(new String(b, 0, n));
        }
        return out.toString();
    }

    @Override
    protected String doInBackground(Void... params) {
        HttpClient httpClient = new DefaultHttpClient();
        HttpContext localContext = new BasicHttpContext();
        String question = questionText.getText().toString();
        String newString = httpPath + "?userText=" + question;
        Log.i("Message", newString);
        HttpGet httpGet = new HttpGet(newString);
        String text = null;
        try {
            HttpResponse response = httpClient.execute(httpGet,
                    localContext);
            HttpEntity entity = response.getEntity();
            text = getASCIIContentFromEntity(entity);


        } catch (Exception e) {
            return e.getLocalizedMessage();
        }
        return text;
    }


    protected void onPostExecute(String results) {
        if (results != null) {
            Log.i("String", results);
        }
    }
}
4

2 回答 2

2

这是从 JSON 字符串中提取数据的方法

JSONObject obj =  new JSONObject(YourJSONString);
String id = obj.getString("id");
String name = obj.getString("name");
于 2012-09-29T00:06:39.070 回答
1

这是你想要的吗：：

HttpGet httpGet = new HttpGet(newString);
String text = null;
    try {
          HttpResponse response = httpClient.execute(httpGet, localContext);
          InputStream content = response.getEntity().getContent();
          BufferedReader buffer = new BufferedReader(new InputStreamReader(content));

          while ((text = buffer.readLine()) != null) {

              //Work with "text" here...
             //Split the string as you wish with "text.split();" function..

             }
         } catch (Exception e) {
            return e.getLocalizedMessage();
         }
于 2012-09-29T06:12:53.703 回答