我正在尝试使用 Twitter-Bootstrap 模式运行 django 表单。我想知道/表单提交后我应该怎么做才能返回。我的views和templates在下面。
网址.py
urlpatterns = patterns('myapp.views',
url(r'^$', 'main'),
url(r'^add/', 'form_add'),
)
视图.py
def main(request):
if request.method == 'POST':
form = MyModelForm(request.POST)
if form.is_valid():
name = form.cleaned_data['name']
request.session['name'] = name
mm = MyModel.objects.create(name=name)
mm.save()
return HttpResponseRedirect('/add') # Redirect after POST
else:
form = MyModelForm()
args = {}
args['last_item'] = MyModel.objects.all().order_by('pk').reverse()[0]
args['form'] = form
return render(request, 'form.html', args)
def form_add(request):
args = {}
name = request.session['name']
return render(request, 'add.html', args)
表单.html
{% extends "base.html" %}
{% block content %}
<button type="button" data-toggle="modal"
data-target="#myModal1">Launch modal</button>
<div class="modal" id="myModal1" tabindex="-1" role="dialog"
aria-labelledby="myModal1Label" aria-hidden="true" style="display: none">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h3 id="myModal1Label">Modal header</h3>
</div>
<div class="modal-body">
<form method="POST" id="" action="">
{% csrf_token %}
{{ form.as_p }}
<button>Submit</button>
</form>
</div>
</div>
<p>Last item: {{ last_item }}</p>
{% endblock %}
{% block scripts %}
{% endblock %}