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假设我有一些航空公司的航班数据。一个字段是始发机场，另一个字段是目的地机场。我想按路线（独特的起点到目的地组合）对观察进行分组。问题是，对于每条独特的路线，还需要包括相应的返回路线。例如，如果我有机场 A 到机场 B 进行一组观察，但在接下来的几次观察中从机场 B 到机场 A，我希望它们都具有相同的路线 ID。

我可以为此使用 SAS、Stata 或 R。即使是 Python，如果它更容易的话。

代表代码如下：

df1 <- structure(list(airl = c("US", "US", "US", "US", "US", "US", "US", 
"US", "US", "US", "US", "US", "US", "US", "US", "US", "US", "US", 
"US", "US", "US", "US", "US", "US", "US", "US", "US", "US", "US", 
"US", "US", "US", "US", "US", "US", "US", "US", "US", "US", "US", 
"US", "US", "US", "US", "US", "US", "US", "US", "US", "US", "US", 
"US", "US", "US", "US", "US", "US", "US", "US", "US", "US", "US", 
"US", "US", "US", "US", "US", "US", "US"), ORIGIN = c("ABE", 
"ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", 
"ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", 
"ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", 
"ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "CLT", "CLT", "CLT", 
"CLT", "CLT", "CLT", "CLT", "CLT", "CLT", "CLT", "CLT", "CLT", 
"CLT", "CLT", "CLT", "CLT", "CLT", "CLT", "PHL", "PHL", "PHL", 
"PHL", "PHL", "PHL", "PHL", "PHL", "PHL", "PHL", "PHL", "PHL", 
"PHL", "PHL", "PHL", "PHL", "PHL"), DESTINATION = c("CLT", "CLT", 
"CLT", "CLT", "CLT", "CLT", "CLT", "CLT", "CLT", "CLT", "CLT", 
"CLT", "CLT", "CLT", "CLT", "CLT", "CLT", "PHL", "PHL", "PHL", 
"PHL", "PHL", "PHL", "PHL", "PHL", "PHL", "PHL", "PHL", "PHL", 
"PHL", "PHL", "PHL", "PHL", "PHL", "ABE", "ABE", "ABE", "ABE", 
"ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", 
"ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", 
"ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", "ABE", 
"ABE", "ABE", "ABE", "ABE"), miles = c(480, 480, 480, 480, 480, 
480, 480, 480, 480, 480, 480, 480, 480, 480, 480, 480, 480, 54, 
54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 
480, 480, 480, 480, 480, 480, 480, 480, 480, 480, 480, 480, 480, 
480, 480, 480, 480, 480, 54, 54, 54, 54, 54, 54, 54, 54, 54, 
54, 54, 54, 54, 54, 54, 54, 54), orig_area = c(23, 23, 23, 23, 
23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 
23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 36, 36, 
36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 
23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 
23), dest_area = c(36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 36, 
36, 36, 36, 36, 36, 36, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 
23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 
23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 
23, 23, 23, 23, 23, 23, 23, 23, 23, 23), month = c(1, 2, 3, 4, 
5, 6, 7, 8, 9, 10, 11, 12, 1, 2, 3, 4, 5, 4, 5, 6, 7, 8, 9, 10, 
11, 12, 1, 2, 3, 4, 5, 6, 7, 8, 10, 11, 12, 1, 2, 3, 4, 5, 6, 
7, 8, 9, 10, 11, 12, 1, 2, 3, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 
1, 2, 3, 4, 5, 6, 7), freq = c(88, 80, 89, 78, 88, 83, 85, 80, 
76, 79, 76, 81, 86, 65, 62, 60, 82, 137, 138, 142, 144, 149, 
147, 150, 143, 150, 138, 128, 151, 145, 148, 146, 147, 149, 79, 
76, 81, 86, 65, 62, 60, 82, 82, 82, 84, 81, 83, 81, 85, 84, 76, 
85, 143, 137, 138, 142, 143, 151, 147, 150, 143, 150, 137, 128, 
151, 145, 148, 146, 147), seats = c(8146, 7352, 7599, 6920, 6759, 
6060, 6189, 5939, 6137, 6504, 6440, 6804, 6862, 5330, 5242, 5068, 
6204, 6460, 6276, 6047, 6095, 6306, 6102, 6265, 7085, 7344, 6809, 
6348, 6965, 6626, 6893, 6741, 6765, 6865, 6504, 6440, 6804, 6862, 
5330, 5242, 5068, 6204, 6104, 6030, 6278, 6034, 6944, 6816, 6544, 
6494, 5872, 6544, 6747, 6460, 6276, 6034, 6058, 6380, 6102, 6278, 
7085, 7344, 6759, 6348, 6952, 6613, 6919, 6728, 6765), year = c(2009, 
2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 
2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 
2010, 2010, 2010, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 
2009, 2009, 2009, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 
2010, 2010, 2010, 2010, 2011, 2011, 2011, 2010, 2010, 2010, 2010, 
2010, 2010, 2010, 2010, 2010, 2010, 2011, 2011, 2011, 2011, 2011, 
2011, 2011)), .Names = c("airl", "ORIGIN", "DESTINATION", "miles", 
"orig_area", "dest_area", "month", "freq", "seats", "year"), class = "data.frame", row.names = c(NA, 
69L))
4

4 回答 4

2

采用最简单的标签（两个机场代码，按字母顺序列出，因此出发地和目的地无关紧要）：

df1$group <- apply(df1[c("ORIGIN", "DESTINATION")], 
                   1, 
                   function(cit) {paste(sort(cit),collapse="-")})

简而言之，只提取机场代码，对于每一行，按字母顺序对代码进行排序，然后用连字符将它们分开粘贴。分配该group变量。

> df1$group
 [1] "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT"
 [8] "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT"
[15] "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL"
[22] "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL"
[29] "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-CLT"
[36] "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT"
[43] "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-CLT"
[50] "ABE-CLT" "ABE-CLT" "ABE-CLT" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL"
[57] "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL"
[64] "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL" "ABE-PHL"
于 2012-09-28T20:18:59.123 回答
1

在 Stata 中，您可以利用字符串之间的关系：

assert "ABE"<"CLT"

很好，虽然当然任何

assert "ABE"<"CLT"
assert "ABE"<1

会产生错误（第一个是假的，第二个是比较不兼容的数据类型）。因此，在 R 中反映 Brian 的建议，我们可以

gen str7 route = origin + "-" + destination if origin < destination & !missing(origin) & !missing(destination)
replace  route = destination + "-" + origin if destination < origin & !missing(origin) & !missing(destination)
list origin destination route if missing( route )

当然，所有缺失值检查都只是妄想症。但是谁知道你的数据有多糟糕:)。

于 2012-09-28T22:14:56.613 回答
1

一种使用R和的方法data.table（用于编码优雅和内存效率）

library(data.table)
DT <- as.data.table(df1)


DT[, id := paste(sort(c(ORIGIN, DESTINATION)), collapse ='-') ,
      by = list(ORIGIN, DESTINATION)]
于 2012-10-02T03:49:32.750 回答
0

SAS 解决方案，使用 PROC FORMAT。我在这里采取的步骤比您可能需要的要多得多 - 只是将每个步骤分开以明确我在做什么。这将为每一对分配一个值，并将该对的两个方向分配给相同的值。

您可以通过使用格式将“ABQ-DEN”或“DEN-ABQ”转换为“ABQ-DEN”来执行与标签本身作为组定义的 R 解决方案完全相同的操作 - 这样做，但设置label=start 在 pre-proc 排序数据步骤中。您还需要将 INFORMAT 转换为 FORMAT。

proc format;
*What this will look like - this is an example and NOT used in the final solution;
invalue $AIRRT
'ABE-CLT'=1
'CLT-ABE'=1
'ABE-PHL'=2
'PHL-ABE'=2
'ABQ-DEN'=3
'DEN-ABQ'=3
'ABQ-ELP'=4
'ELP-ABQ'=4
'MDW-MCI'=5
;
*Only used to create sample data;
value AIRPORT
1="ABE"
2="CLT"
3="PHL"
4="ABQ"
5="ELP"
6="DEN"
7="MDW"
8="MCI"
;
quit;

*create sample data;
data have;
do _t = 1 to 100;
    origin=put(ceil(8*ranuni(7)),$AIRPORT.);
    do until (destination ne origin);
        destination=put(ceil(8*ranuni(7)),AIRPORT.);
    end;
    output;
end;
run;

*create preliminary dataset for format, creating combined field;
data for_format_pre;
 set have;
 call sortc(of origin destination);
 start = catx('-',origin,destination); 
 keep start origin destination;
run;

*sort down to one per route;
proc sort nodupkey data=for_format_pre;
 by start;
run;

*create final format dataset, with group counter;
data for_format;
set for_format_pre;
 retain fmtname "AIRRT" type 'j';
 label+1;
 output;
 start=catx('-',destination,origin);
 output;
run;

*import into formats;
proc format cntlin=for_format;
quit;

*apply to dataset;
data want;
set have;
combined=catx('-',origin,destination);
group_sort = input(combined,$AIRRT.);
drop _:;
run;
于 2012-09-28T20:43:35.107 回答