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在 Firefox 中执行以下测试时，org.openqa.selenium.ElementNotVisibleException: Element is not currently visible and so may not be interacted with会抛出“”。原因似乎是在使用 Select 字段（变量 selectMarke）之前出现的弹出窗口（奇怪的是，在手动单击该站点时不会出现）。我尝试了几种在不同线程中列出的可能性，但没有奏效。原因似乎是弹出窗口。

我该如何解决这个问题？

    FirefoxProfile profile = new FirefoxProfile();
    profile.setEnableNativeEvents(true);
    WebDriver driver = new FirefoxDriver(profile);
    driver.manage().timeouts().implicitlyWait(16, TimeUnit.SECONDS);

    driver.get("http://www.autoscout24.de/");
    System.out.println("Page title is: " + driver.getTitle());
    WebElement pageWSuche = driver.findElement(By.linkText("Werkstattsuche"));
    pageWSuche.click();

    WebElement plzField = driver.findElement(By.id("cms-plz"));
    plzField.sendKeys("81243");

    WebElement findGarField = driver.findElement(By.cssSelector("span.buttonBob span input[value='Werkstätten finden']"));
    findGarField.click();

    WebElement navInspect = driver.findElement(By.linkText("Inspektion (mit Preis)"));
    navInspect.click();

    Select selectMarke = new Select(driver.findElement(By.cssSelector("select.inputL[name='MakeId']")));
    selectMarke.selectByVisibleText("BMW");

    driver.quit();

在同一域但在不同页面中执行以下类时，一切都很好，因为不会出现弹出窗口。

    FirefoxProfile profile = new FirefoxProfile();
    profile.setEnableNativeEvents(true);
    WebDriver driver = new FirefoxDriver(profile);
    driver.manage().timeouts().implicitlyWait(16, TimeUnit.SECONDS);

    driver.get("http://www.autoscout24.de/");
    WebElement element = driver.findElement(By.linkText("Fahrzeugsuche"));
    element.click();

    Select selectMarke = new Select(driver.findElement(By.cssSelector("select.inputFullWidth[name='make1']")));
    selectMarke.selectByVisibleText("BMW");
    Select selectModell = new Select(driver.findElement(By.cssSelector("select.inputFullWidth[name='model1']")));
    selectModell.selectByValue("15779");
    Select selectPriceTo = new Select(driver.findElement(By.cssSelector("select.inputFullWidth[name='priceto']")));
    selectPriceTo.selectByVisibleText("100.000");
    Select selectYearFrom = new Select(driver.findElement(By.cssSelector("select.inputFullWidth[name='yearfrom']")));
    selectYearFrom.selectByVisibleText("2006");
    Select selectKM = new Select(driver.findElement(By.cssSelector("select.inputFullWidth[name='mileageto']")));
    selectKM.selectByVisibleText("200.000");
    Select selectFuel = new Select(driver.findElement(By.cssSelector("select.inputFullWidth[name='fuel']")));
    selectFuel.selectByVisibleText("Diesel");
    WebElement location = driver.findElement(By.id("zipcode"));
    location.sendKeys("München");
    Select selectRadius = new Select(driver.findElement(By.cssSelector("select.inputFullWidth[name='zipradius']")));
    selectRadius.selectByVisibleText("200 km");

    WebElement searchBtn = driver.findElement(By.cssSelector("input[value$='Fahrzeuge']"));
    searchBtn.click();

    driver.quit();
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2 回答 2

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这真的不应该发生。实际上，硒在判断元素是否可见方面非常聪明。以下代码直接从 Selenium 原子复制：

 // Any element with a display style equal to 'none' or that has an ancestor  
 // with display style equal to 'none' is not shown.  
 function displayed(e) {    
     if (bot.dom.getEffectiveStyle(e, 'display') == 'none') {      
         return false;    
     }        
     var parent = bot.dom.getParentElement(e);   
     return !parent || displayed(parent);  
 }

这允许子元素覆盖父元素的display:none. 也许还有其他问题？

一种替代方法是使用 jquery 手动单击提交。Autoscout24提到了 jquery，所以它应该已经嵌入到页面中。然后你可以使用类似的东西

//searchBtn.click();
((JavascriptExecutor) driver).executeScript("$(arguments[0]).click();", searchBtn);

这样，您可以绕过 selenium 对元素是否可见的检查。我希望这会有所帮助。

于 2012-10-05T20:06:03.913 回答
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我会用这样的方法来做到这一点，专为寻找元素上的 display:none 标志：

public Boolean elementIsDisplayed( By locator ) {   
    Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
        .withTimeout(30, TimeUnit.SECONDS)
        .pollingEvery(5, TimeUnit.SECONDS)
        .ignoring(NoSuchElementException.class, StaleElementReferenceException.class);
    WebElement foo = wait.until( 
         ExpectedConditions.visibilityOfElementLocated( locator );
    if ( foo == null ) return false;
    return true;
}
于 2013-11-12T17:25:19.493 回答