我正在尝试制作一个“锦标赛”应用程序，并且卡在查看来自 6 个不同表的数据！
我有6个表可以同时放入数据，但是不能一起查看！并试图在互联网上搜索几个小时，但我就是无法得到它......
反正。这是一场 4 队锦标赛，有赢、平、输和积分。为此，我有 6 张桌子：
- 比赛名称 - ID、名称
- 团队 - ID、团队 1、团队 2、团队 3、团队 4
- 获胜 - ID、team1w、team2w、team3w、team4w
- 绘制 ID、team1d、team2d、team3d、team4d
- 松动 - ID、team1l、team2l、team3l、team4l
- 积分 - ID、team1p、team2p、team3p、team4p
这就是表格中的内容...
这是我的输入，它工作正常..
<?php
if(isset($_POST['submit'])) {
$cupname = $_POST['cupname'];
$team1 = $_POST['team1'];
$team2 = $_POST['team2'];
$team3 = $_POST['team3'];
$team4 = $_POST['team4'];
$zero = "0";
$result = mysql_query("INSERT INTO cupname (name) VALUES ('$cupname')");
$result = mysql_query("INSERT INTO teams (team1, team2, team3, team4) VALUES ('$team1', '$team2', '$team3', '$team4')");
$result = mysql_query("INSERT INTO wins (team1w, team2w, team3w, team4w) VALUES ($zero, $zero, $zero, $zero)");
$result = mysql_query("INSERT INTO draws (team1d, team2d, team3d, team4d) VALUES ($zero, $zero, $zero, $zero)");
$result = mysql_query("INSERT INTO looses (team1l, team2l, team3l, team4l) VALUES ($zero, $zero, $zero, $zero)");
$result = mysql_query("INSERT INTO points (team1p, team2p, team3p, team4p) VALUES ($zero, $zero, $zero, $zero)");
echo "<h1>Turnering og lag lagt til!</h1>";
}
?>
这就是制作“联赛/锦标赛”的开始。所有的数据都在表格中。
我从一个教程中获得了这段代码，该教程用于为我的网页进行简单的现场编辑。虽然我可以使用相同的输出代码，但在那个站点上它只是来自单个表的新闻。
我已经阅读了一些关于 UNION、LEFT JOIN、FULL JOIN 等的信息……但我没有明白。
这是我的“输出”代码：
<?php
$result = mysql_query("SELECT * FROM cupname ORDER BY id DESC");
$result = mysql_query("SELECT * FROM teams ORDER BY id DESC");
$result = mysql_query("SELECT * FROM wins ORDER BY id DESC");
$result = mysql_query("SELECT * FROM draws ORDER BY id DESC");
$result = mysql_query("SELECT * FROM looses ORDER BY id DESC");
$result = mysql_query("SELECT * FROM points ORDER BY id DESC");
while($row = mysql_fetch_array($result)) {
$i=$i + 1;
echo "<table>";
echo "<tr>";
echo $row['name'];
echo "</tr>";
echo "<tr><td><b>Lag</b></td>
<td><b>Seiere</b></td>
<td><b>Uavgjort</b></td>
<td><b>Tap</b></td>
<td><b>Poeng</b></td>
</tr><tr><td>";
echo $row['team1'];
echo "</td><td>";
echo $row['team1w'];
echo "</td><td>";
echo $row['team1d'];
echo "</td><td>";
echo $row['team1l'];
echo "</td><td>";
echo $row['team1p'];
echo "</td></tr><tr><td>";
echo $row['team2'];
echo "</td><td>";
echo $row['team2w'];
echo "</td><td>";
echo $row['team2d'];
echo "</td><td>";
echo $row['team2l'];
echo "</td><td>";
echo $row['team2p'];
echo "</td></tr><tr><td>";
echo $row['team3'];
echo "</td><td>";
echo $row['team3w'];
echo "</td><td>";
echo $row['team3d'];
echo "</td><td>";
echo $row['team3l'];
echo "</td><td>";
echo $row['team3p'];
echo "</td></tr><tr><td>";
echo $row['team4'];
echo "</td><td>";
echo $row['team4w'];
echo "</td><td>";
echo $row['team4d'];
echo "</td><td>";
echo $row['team4l'];
echo "</td><td>";
echo $row['team1p'];
echo "</td></tr></table><br /><hr /><br />";
}
?>
有人知道我应该做什么，或者不做什么吗？
感谢您的任何回答！
编辑：我只是得到一个空表的输出！仅输出点，即 0。