4

ICommandHandler<T>我需要使用相应DeadlockRetryCommandHandlerDecorator<T>类型根据类型装饰所有内容

我尝试了这个解决方案，但不幸的是它不起作用。

container.Register(
    Component.For(typeof(ICommandHandler<>))
    .ImplementedBy(typeof(DeadlockRetryCommandHandlerDecorator<>)));

container.Register(
    AllTypes.FromThisAssembly()
        .BasedOn(typeof(ICommandHandler<>))
        .WithService.Base());

我如何注册一个通用装饰器（DeadlockRetryCommandHandlerDecorator<T>）来包装所有通用ICommandHandler<T>实现？

4

2 回答 2

1

目前不支持 OOTB，因为 Windsor 总是更喜欢模式特定组件而不是开放通用组件。

你可以很容易地让它工作ISubDependencyResolver。下面的代码假设您为装饰器命名组件"DeadlockRetryCommandHandlerDecorator"

public class CommandHandlerResolver : ISubDependencyResolver
{
    private readonly IKernel kernel;

    public FooResolver(IKernel kernel)
    {
        this.kernel = kernel;
    }

    public bool CanResolve(CreationContext context, ISubDependencyResolver contextHandlerResolver, ComponentModel model, DependencyModel dependency)
    {
        return (dependency.TargetType.IsGenericType &&
                dependency.TargetType.GetGenericTypeDefinition() == typeof (ICommandHandler<>)) &&
                (model.Implementation.IsGenericType == false ||
                model.Implementation.GetGenericTypeDefinition() != typeof (DeadlockRetryCommandHandlerDecorator<>));
    }

    public object Resolve(CreationContext context, ISubDependencyResolver contextHandlerResolver, ComponentModel model, DependencyModel dependency)
    {
        return kernel.Resolve("DeadlockRetryCommandHandlerDecorator", dependency.TargetItemType);
    }
}

然而，使用 Windsor 实现类似场景的推荐方法是使用拦截器。

于 2012-09-29T00:49:26.837 回答
0

我遇到过同样的问题。我设法通过将每种类型显式注册为更具体的类型来解决它。对我来说，这个解决方案比使用子依赖解析器更清楚

var commandTypes = businessAssembly.GetTypes()
    .Where(t => !t.IsInterface && typeof(ICommand).IsAssignableFrom(t));

foreach(var commandType in commandTypes)
{
    var handlerInterface = typeof(ICommandHandler<>).MakeGenericType(new[] { commandType });
    var transactionalHandler = typeof(DeadlockRetryCommandHandlerDecorator<>).MakeGenericType(new[] { commandType });
    container.Register(Component.For(handlerInterface)
        .ImplementedBy(transactionalHandler)
        .LifeStyle.PerWebRequest);
}
于 2015-11-22T17:02:32.740 回答