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我有一个具有以下语法的输入文件：

"ID","Company Name","AccountManager","Product","Support Type","Country"

例子：

"1","Company one","Surname Name / Phone/ Cell Phone ","Product► (d2XXXXXX) ► Version","29.10.2012 ► Type of support","Singapore"

"2","Company two","Surname Name / Phone/ Cell Phone ","Product► (d2XXXXXX) ► Version\nProduct► (d2XXXXXX) ► Version\nProduct► (d2XXXXXX) ► Version","31.10.2012 ► Type of support\n28.10.2012 ► Type of support\nn/a ► Type of support","Indonesia"

"3","Company three","Surname Name / Phone/ Cell Phone ","Product► (d2XXXXXX) ► Version\nProduct► (d2XXXXXX) ► Version\nProduct► (d2XXXXXX) ► Version\nProduct► (d2XXXXXX) ► Version\nProduct► (d2XXXXXX) ► Version\nProduct► (d2XXXXXX) ► Version,"31.12.2012 ► Type of support\nType of support\nn\\a ► Type of support\n31.03.2013 ► Type of support\n25.10.2012 ► Type of support\nn\\a ► Type of support","USA"

第一个公司只有一个产品，第二个公司有 3 个产品 - 它们用\n(Product and Support Type) 分隔，第三个公司有 6 个产品。

在输出中，此字符串必须是单独的并重复列的值：

"ID","Company Name","AccountManager","Country"，但"AccountManager"应该只有姓氏和姓名，并且支持类型列应该与今天日期进行比较 - 如果支持类型中的日期与今天的日期在 27 到 32 天之间的值不同，则此列必须在输出文件中。如果我们获得n/a了支持类型，则应该错过它。

输出应如下所示：

"1","Company one","Surname Name","Product► (d2XXXXXX) ► Version","29.10.2012","Singapore"
"2","Company two","Surname Name","Product► (d2XXXXXX) ► Version","28.10.2012","Indonesia"
"2","Company two","Surname Name","Product► (d2XXXXXX) ► Version","31.10.2012","Indonesia"
"3","Company three","Surname Name","Product► (d2XXXXXX) ► Version","25.10.2012","USA"

我怎样才能在 bash 中做到这一点？

4

1 回答 1

2

您可以使用以下名为“products.awk”的 AWK 脚本来获取它：

#/usr/bin/awk -f

BEGIN {
    FS=",";
    "date +\"%s\"" | getline curr_timestamp;
}

{
    split($3, account, "/");
    gsub(/ $/, "", account[1]);
    split($4, products, "\\\\n");
    split($5, supports, "\\\\n");
    for (i in products) {
        gsub("\"", "", products[i]);
        gsub("\"", "", supports[i]);
        split(supports[i], timesupport, " ");
        # ignore not available and support without date
        if (supports[i] !~ /n\\\\a*/ && supports[i] !~ /n\/a*/ && $2 !~ /\NULL/ && timesupport[1] ~ /[0-9][0-9].[0-9][0-9].[0-9][0-9][0-9][0-9]/) {
            # formatting date
            split(timesupport[1], date, "\.");
            mydate = "date -d \""date[3]"/"date[2]"/"date[1]"\" \"+%s\"";
            # date to timestamp (using bash)
            mydate | getline timestamp;
            # timestamp is >= 27 days and <= 32 days
            if ((timestamp-curr_timestamp) >= 2332800 && (timestamp-curr_timestamp) <= 2764800)
                print $1","$2","account[1]"\",\""products[i]"\",\""supports[i]"\","$6;
        }
    }
}

假设您的数据位于名为 data.txt 的文件中，您可以使用以下行从 bash 调用此脚本：

awk -f products.awk data.txt

使用您的示例文件，我得到了运行脚本的输出：

"1","Company one","Surname Name","Product► (d2XXXXXX) ► Version","29.10.2012 ► Type of support","Singapore"
"2","Company two","Surname Name","Product► (d2XXXXXX) ► Version","31.10.2012 ► Type of support","Indonesia"
"2","Company two","Surname Name","Product► (d2XXXXXX) ► Version","28.10.2012 ► Type of support","Indonesia"

编辑：

我只得到 3 行，因为最后一行不适合 >= 27 && <= 32 条件（今天是 9 月 29 日，您的问题是 9 月 28 日提出的）。

终于我们明白了！！

于 2012-09-28T06:57:30.620 回答