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我有一个如下所示的 xml

        string input =
@"<g1:Person xmlns:g1=""http://api.google.com/staticInfo/"">
    <g1:Id>005008</g1:Id>
    <g1:Infolist>
 <g1:Info><g1:Title>a</g1:Title></g1:Info>    
<g1:Info<g1:Title>b</g1:Title></g1:Info>     
<g1:Info><g1:Title>c</g1:Title></g1:Info>
<g1:overview>there are three chaters.</g1:overview>
  </g1:Infolist>
    <g1:age>23</g1:age>
  </g1:Person>";

我定义了对象，但我不知道将 /Person/Infolist/overview 放在哪里。这个属性如何定义。放在哪里。

   [XmlRoot(ElementName = "Person", Namespace = "http://api.google.com/staticInfo/")]
    public class Person
    {

        public int Id { get; set; }

        public int age { get; set; }

        [XmlElement(ElementName = "Infolist", Namespace = "http://api.google.com/staticInfo/")]
        public List<Info> Infolist {get;set; }
    }

    public class Info
    {
        public int Title { get; set; }
    }
4

1 回答 1

1 
//------------------------------------------------------------------------------
// <auto-generated>
//     This code was generated by a tool.
//     Runtime Version:4.0.30319.269
//
//     Changes to this file may cause incorrect behavior and will be lost if
//     the code is regenerated.
// </auto-generated>
//------------------------------------------------------------------------------

using System.Xml.Serialization;

// 
// This source code was auto-generated by xsd, Version=4.0.30319.1.
// 


/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true, Namespace="http:=//api.google.com/staticInfo/")]
[System.Xml.Serialization.XmlRootAttribute(Namespace="http:=//api.google.com/staticInfo/", IsNullable=false)]
public partial class Person {

    /// <remarks/>
    public ushort Id;

    /// <remarks/>
    public PersonInfolist Infolist;

    /// <remarks/>
    public byte age;
}

/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true, Namespace="http:=//api.google.com/staticInfo/")]
public partial class PersonInfolist {

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute("Info")]
    public string[] Info;

    /// <remarks/>
    public string overview;
}

脚步：

  • 将您的 Xml 粘贴到 Visual Studio 中的新 Xml 文件中
  • 单击 Xml -> 创建架构
  • 将架构文件保存到磁盘
  • 打开 Visual Studio 命令提示符
  • 执行命令：xsd /classes /fields so.xsd

这可能是获得结果的众多方法之一。我喜欢让工具生成我的代码——它们永远不会出错。

于 2012-09-28T02:02:27.183 回答