1

我必须序列化一个CList基类和派生类。我怎样才能做到这一点。

typedef CList<Student*, Student*> StVec;

class Student : public CObject
{
public:
    DECLARE_SERIAL(Student);

    Student();
    Student(Student& s);
    Student(CString _name, CString _last, int _age);
    virtual ~Student(void);

    virtual void cin();
    virtual void cout();

    virtual void Serialize(CArchive& ar);

    static Student* FromInput();

    inline const CString GetName(){return name;}
    inline const CString GetLastName(){return last_name;}
    inline const int GetAge(){return age;}

    virtual inline Student& operator=( const Student &s ) 
    { 
        name = s.name; 
        last_name = s.last_name;
        age = s.age;
        return *this; 
    }

protected:
    CString name;
    CString last_name;
    int age;
};

class Warden : public Student
{
protected:
    virtual void Serialize(CArchive& ar);
    UINT salary;
};

class Group : public CObject
{
public: 
    DECLARE_SERIAL(Group);

    enum FindType { First = 0, Last, All};
    typedef bool (*StudentsFindCallback) (Student* student, void* condition);

    Group(){ name = _T("Default Group"); }
    Group(CString _name);
    Group(Group& s);

    ~Group();

    void CreateUser();
    void ShowUsers();
    //StVecOfIt FindUser(StudentsFindCallback f, void* condition, FindType ft);
    inline Student* getStudent(POSITION pos) {return students->GetNext(pos); }
    inline void DeleteUser(POSITION it){ students->RemoveAt(it); }
    virtual void Serialize(CArchive& ar);
    void Clean();

    /*static bool FindbyName(Student* student, void* condition);
    static bool FindbyLastName(Student* student, void* condition);
    static bool FindbyAge(Student* student, void* condition);*/

    virtual inline Group& operator=( const Group &s ) 
    { 
        name = s.name; 
        students = s.students;
        return *this; 
    }

protected:
    CString name;
    StVec* students;
};

void Student::Serialize(CArchive& ar)
{
    CObject::Serialize( ar );

    if (ar.IsStoring())
    {   
        ar.SerializeClass(Student::GetRuntimeClass());      
        ar << name << last_name << age;
    }
    else 
    {
        ar.SerializeClass(Student::GetRuntimeClass());
        ar >> name >> last_name >> age;
    }   
}
void Group::Serialize(CArchive& ar)
{
    ar.SerializeClass(RUNTIME_CLASS(Group));

    if (ar.IsStoring())
    {
        ar << (int)students->GetCount();

        POSITION pos = students->GetHeadPosition();
        while(pos != NULL)
        {
            Student* student = students->GetNext(pos);

            student->Serialize(ar);
        }
    }
    else 
    {       
        Clean();
        int count = 0;
        ar >> count;

        for(INT_PTR i = 0; i < count; ++i)
        {
            Student* st = new Student();
            st->Serialize(ar);
            students->AddTail(st);
        }
    }
}

我在codeproject上找到了一篇文章,但我根本无法理解。

当然,我可以添加一个指示类类型的标志。我也可以序列化到派生类,如果派生属性为空static_cast,则可以将其派生到基类。或者我正在考虑使用CArchive::ReadObjectCArchive::ReadClass加载类,但还有其他方法吗?

4

1 回答 1

0

我的 MFC 生锈了,但我相信这应该可以工作(未经测试!)。

此外,您的 Serialize() 方法永远不应为其自己的类调用 SerializeClass。由调用者决定调用它。例如,<< 和 >> 运算符这样做是为了识别归档中接下来出现的对象的类。

void Student::Serialize( CArchive& ar ) 
{ 
    CObject::Serialize( ar ); 

    if (ar.IsStoring()) 
    {    // No need for SerializeClass here.
        ar << name << last_name << age; 
    } 
    else  
    {    // No need for SerializeClass here.
        ar >> name >> last_name >> age; 
    }    
} 
void Group::Serialize(CArchive& ar) 
{ 
    if (ar.IsStoring()) 
    { 
        ar << (int)students->GetCount(); 

        POSITION pos = students->GetHeadPosition(); 
        while(pos != NULL) 
        { 
            Student* student = students->GetNext(pos); 
           ar << student; // << includes class info about the serialized object
        } 
    } 
    else  
    {        
        Clean(); 
        int count = 0; 
        ar >> count; 

        for(INT_PTR i = 0; i < count; ++i) 
        { 
            CObject *p;
            ar >> p; // Deserialize whatever kind of object comes next
            students->AddTail(p); 
        } 
    } 
} 
于 2012-09-30T17:02:20.730 回答