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我正在尝试在 mySQL 的 IF 子句中使用 LIKE 并收到错误。

SELECT nc.web_name AS company_name,
    IF((b.booth_number LIKE '%Cafe%', b.booth_number, substring(b.booth_number,4)) AS booth_number, 
    nc.site_url AS website, IF (nc.ismi_status = 1, 'Member','') AS member_status 
    FROM booth_sale bs JOIN {ismi.booth} b ON bs.booth_id = b.booth_id 
    JOIN ismi.new_people np ON bs.contact_id = np.id 
    JOIN ismi.new_company nc ON nc.id = np.company_id 
    WHERE b.show_event_id = 298 AND status IN(44,45) ORDER BY 3

如果我这样做，查询工作正常：

IF((b.booth_number = 'Cafe', b.booth_number, substring(b.booth_number,4)) AS booth_number

但我需要检查多种可能性 - 可能有 Cafe、Cafe1、Cafe2 等，我想返回b.booth_number该字段值包括 Cafe 的任何记录。

这是我得到的错误：

PDOException: SQLSTATE[42000]: 语法错误或访问冲突：1064 您的 SQL 语法有错误；检查与您的 MySQL 服务器版本相对应的手册，以获取正确的语法，以便在第 2 行的 'AS stand_number, nc.site_url AS website, IF (nc.ismi_status = 1, 'Member','') ' 附近使用：SELECT nc. web_name AS company_name, IF((b.booth_number LIKE '%Cafe%', b.booth_number, substring(b.booth_number,4)) ASbooth_number, nc.site_url AS 网站, IF (nc.ismi_status = 1, 'Member' ,'') AS member_status FROM {ismi.booth_sale} bs JOIN {ismi.booth} b ON bs.booth_id = b.booth_id JOIN {ismi.new_people} np ON bs.contact_id = np.id JOIN {ismi.new_company} nc ON nc.id = np.company_id WHERE b.show_event_id = 298 AND status IN(44,45) ORDER BY 3

谁能告诉我我做错了什么，或者是否有其他方法可以做到这一点？

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1 回答 1

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您的IF陈述有一个太多的左括号。删除第一个，你应该会很好（当然，等待任何其他 SQL 错误）：

...
IF(b.booth_number LIKE '%Cafe%', b.booth_number, substring(b.booth_number,4)) AS booth_number, 
...
于 2012-09-27T20:17:04.720 回答