mysql - MySQL - 基于 SELECT Query 的 UPDATE 查询

Question

我需要检查（从同一张表中）两个事件之间是否存在基于日期时间的关联。

一组数据将包含某些事件的结束日期时间，另一组数据将包含其他事件的开始日期时间。

如果第一个事件在第二个事件之前完成，那么我想将它们链接起来。

到目前为止，我所拥有的是：

SELECT name as name_A, date-time as end_DTS, id as id_A 
FROM tableA WHERE criteria = 1


SELECT name as name_B, date-time as start_DTS, id as id_B 
FROM tableA WHERE criteria = 2

然后我加入他们：

SELECT name_A, name_B, id_A, id_B, 
if(start_DTS > end_DTS,'VALID','') as validation_check
FROM tableA
LEFT JOIN tableB ON name_A = name_B

然后，我可以根据我的 validation_check 字段运行一个嵌套了 SELECT 的 UPDATE 查询吗？

score 968 · Accepted Answer

您实际上可以通过以下两种方式之一执行此操作：

MySQL 更新连接语法：

UPDATE tableA a
INNER JOIN tableB b ON a.name_a = b.name_b
SET validation_check = if(start_dts > end_dts, 'VALID', '')
-- where clause can go here

ANSI SQL 语法：

UPDATE tableA SET validation_check = 
    (SELECT if(start_DTS > end_DTS, 'VALID', '') AS validation_check
        FROM tableA
        INNER JOIN tableB ON name_A = name_B
        WHERE id_A = tableA.id_A)

选择对你来说最自然的一个。

score 380 · Accepted Answer

UPDATE
    `table1` AS `dest`,
    (
        SELECT
            *
        FROM
            `table2`
        WHERE
            `id` = x
    ) AS `src`
SET
    `dest`.`col1` = `src`.`col1`
WHERE
    `dest`.`id` = x
;

希望这对你有用。

score 158 · Accepted Answer

在 MySQL 中很容易：

UPDATE users AS U1, users AS U2 
SET U1.name_one = U2.name_colX
WHERE U2.user_id = U1.user_id

score 72 · Accepted Answer

如果有人试图将数据从一个数据库更新到另一个数据库，无论他们针对的是哪个表，都必须有一些标准来做到这一点。

这个对所有级别都更好，更干净：

UPDATE dbname1.content targetTable

LEFT JOIN dbname2.someothertable sourceTable ON
    targetTable.compare_field= sourceTable.compare_field
SET
    targetTable.col1  = sourceTable.cola,
    targetTable.col2 = sourceTable.colb, 
    targetTable.col3 = sourceTable.colc, 
    targetTable.col4 = sourceTable.cold

特拉啊！效果很好！

有了以上了解，您就可以修改设置的字段和“开启”条件来完成您的工作。您还可以执行检查，然后将数据提取到临时表中，然后使用上述语法替换您的表和列名来运行更新。

希望它有效，如果不让我知道。我会为你写一个确切的查询。

score 34 · Accepted Answer

UPDATE 
  receipt_invoices dest,
  (
    SELECT 
      `receipt_id`,
      CAST((net * 100) / 112 AS DECIMAL (11, 2)) witoutvat 
    FROM
      receipt 
    WHERE CAST((net * 100) / 112 AS DECIMAL (11, 2)) != total 
      AND vat_percentage = 12
  ) src 
SET
  dest.price = src.witoutvat,
  dest.amount = src.witoutvat 
WHERE col_tobefixed = 1 
  AND dest.`receipt_id` = src.receipt_id ;

希望这在您必须在两个表之间匹配和更新的情况下对您有所帮助。

score 15 · Accepted Answer

我在寻找自己的解决方案来解决非常复杂的连接时发现了这个问题。对于更复杂的问题版本，这是一种替代解决方案，我认为这可能有用。

我需要填充活动表中的 product_id 字段，其中活动以单位编号，单位以级别编号（使用字符串 ??N 标识），以便可以使用 SKU 标识活动，即 L1U1A1。然后将这些 SKU 存储在不同的表中。

我确定了以下内容以获取 activity_id 与 product_id 的列表：-

SELECT a.activity_id, w.product_id 
  FROM activities a 
  JOIN units USING(unit_id) 
  JOIN product_types USING(product_type_id) 
  JOIN web_products w 
    ON sku=CONCAT('L',SUBSTR(product_type_code,3), 'U',unit_index, 'A',activity_index)

我发现这太复杂了，无法合并到 mysql 中的 SELECT 中，所以我创建了一个临时表，并将其与更新语句连接：-

CREATE TEMPORARY TABLE activity_product_ids AS (<the above select statement>);

UPDATE activities a
  JOIN activity_product_ids b
    ON a.activity_id=b.activity_id 
  SET a.product_id=b.product_id;

我希望有人觉得这很有用

score 8 · Accepted Answer

UPDATE [table_name] AS T1,
      (SELECT [column_name] 
        FROM [table_name] 
        WHERE [column_name] = [value]) AS T2 
  SET T1.[column_name]=T2.[column_name] + 1
WHERE T1.[column_name] = [value];

score 5 · Accepted Answer

您可以像这样使用内部联接更新另一个表中的值

UPDATE [table1_name] AS t1 INNER JOIN [table2_name] AS t2 ON t1.column1_name] = t2.[column1_name] SET t1.[column2_name] = t2.column2_name];

按照此处了解如何使用此查询http://www.voidtricks.com/mysql-inner-join-update/

或者您可以使用 select 作为子查询来执行此操作

UPDATE [table_name] SET [column_name] = (SELECT [column_name] FROM [table_name] WHERE [column_name] = [value]) WHERE [column_name] = [value];

查询在此处详细解释http://www.voidtricks.com/mysql-update-from-select/

score 4 · Accepted Answer

您可以使用：

UPDATE Station AS st1, StationOld AS st2
   SET st1.already_used = 1
 WHERE st1.code = st2.code

score 3 · Accepted Answer

对于同一张桌子，

UPDATE PHA_BILL_SEGMENT AS PHA,
     (SELECT BILL_ID, COUNT(REGISTRATION_NUMBER) AS REG 
       FROM PHA_BILL_SEGMENT
        GROUP BY REGISTRATION_NUMBER, BILL_DATE, BILL_AMOUNT
        HAVING REG > 1) T
    SET PHA.BILL_DATE = PHA.BILL_DATE + 2
 WHERE PHA.BILL_ID = T.BILL_ID;

score 1 · Accepted Answer

我在一个表本身中有重复条目的问题。以下是对我有用的方法。@sibaz 也提倡它。

最后我使用以下查询解决了它：

选择查询保存在临时表中

IF OBJECT_ID(N'tempdb..#New_format_donor_temp', N'U') IS NOT NULL
    DROP TABLE #New_format_donor_temp;

select *
into #New_format_donor_temp
from DONOR_EMPLOYMENTS
where DONOR_ID IN (
  1, 2
)

-- Test New_format_donor_temp
-- SELECT *
-- FROM #New_format_donor_temp;

临时表在更新查询中加入。

UPDATE de
SET STATUS_CD=de_new.STATUS_CD, STATUS_REASON_CD=de_new.STATUS_REASON_CD, TYPE_CD=de_new.TYPE_CD
FROM DONOR_EMPLOYMENTS AS de
  INNER JOIN #New_format_donor_temp AS de_new ON de_new.EMP_NO = de.EMP_NO
WHERE
  de.DONOR_ID IN (
    3, 4
)

我对 SQL 不是很有经验，请告知您知道的任何更好的方法。

以上查询适用于 MySql 服务器。

score 1 · Accepted Answer

如果您从复杂的查询中更新。最好的办法是从查询中创建临时表，然后使用临时表作为一个查询进行更新。

    DROP TABLE IF EXISTS cash_sales_sums;
CREATE TEMPORARY TABLE cash_sales_sums as
SELECT tbl_cash_sales_documents.batch_key, COUNT(DISTINCT tbl_cash_sales_documents.cash_sale_number) no_of_docs,
  SUM(tbl_cash_sales_documents.paid_amount) paid_amount, SUM(A.amount - tbl_cash_sales_documents.bonus_amount - tbl_cash_sales_documents.discount_given) amount,
  SUM(A.recs) no_of_entries FROM 
        tbl_cash_sales_documents
    RIGHT JOIN(
        SELECT
            SUM(
                tbl_cash_sales_transactions.amount
            )amount,
            tbl_cash_sales_transactions.cash_sale_document_id,
            COUNT(transaction_id)recs
        FROM
            tbl_cash_sales_transactions
        GROUP BY
            tbl_cash_sales_transactions.cash_sale_document_id
    )A ON A.cash_sale_document_id = tbl_cash_sales_documents.cash_sale_id
    GROUP BY
        tbl_cash_sales_documents.batch_key
ORDER BY batch_key;





UPDATE tbl_cash_sales_batches SET control_totals = (SELECT amount FROM cash_sales_sums WHERE cash_sales_sums.batch_key = tbl_cash_sales_batches.batch_key LIMIT 1),
expected_number_of_documents = (SELECT no_of_docs FROM cash_sales_sums WHERE cash_sales_sums.batch_key = tbl_cash_sales_batches.batch_key),
computer_number_of_documents = expected_number_of_documents,  computer_total_amount = control_totals
WHERE batch_key IN (SELECT batch_key FROM cash_sales_sums);

score 0 · Accepted Answer

INSERT INTO all_table
SELECT Orders.OrderID,
    Orders.CustomerID,
    Orders.Amount,
    Orders.ProductID,
    Orders.Date,
    Customer.CustomerName,
    Customer.Address
FROM Orders
JOIN Customer ON Orders.CustomerID=Customer.CustomerID
WHERE Orders.OrderID not in (SELECT OrderID FROM all_table)

mysql - MySQL - 基于 SELECT Query 的 UPDATE 查询

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