我创建了一个新闻模型。我的新闻有一位作者属于会员类别。这足以设置外键吗？
HasRequired(n => n.Author);
代码：
public class Member : Identity
{
public string FirstName { get; set; }
public string LastName { get; set; }
public string Email { get; set; }
public Address Address { get; set; }
public int Id { get; set; }
public virtual ICollection<News> News { get; set; }
}
public class News
{
public string Title { get; set; }
public string Subtile { get; set; }
public int Id { get; set; }
public string Url { get; set; }
public DateTime DateAdded { get; set; }
public virtual Member Author;
}
public class NewsMap : EntityTypeConfiguration<News>
{
public NewsMap()
{
HasKey(n => n.Id);
Property(n => n.Id).
HasDatabaseGeneratedOption(DatabaseGeneratedOption.Identity)
.HasColumnName("Id");
Property(t => t.Title)
.IsRequired()
.HasMaxLength(100)
.IsUnicode();
Property(t => t.Subtile)
.IsRequired()
.HasMaxLength(100)
.IsUnicode();
Property(t => t.Url)
.IsRequired()
.HasMaxLength(255)
.IsUnicode();
Property(t => t.DateAdded).HasColumnName("DateAdded")
.HasDatabaseGeneratedOption(DatabaseGeneratedOption.Computed);
HasRequired(n => n.Author); //is this enough for the foreing key to be set?
}
}
public class MemberMap : EntityTypeConfiguration<Member>
{
public MemberMap()
{
// Primary Key
this.HasKey(t => t.Id);
// Properties
this.Property(t => t.FirstName)
.IsRequired()
.HasMaxLength(150);
this.Property(t => t.LastName)
.IsRequired()
.HasMaxLength(50);
this.Property(t => t.Email)
.IsRequired()
.HasMaxLength(150);
this.Property(t => t.Address.Id)
.IsRequired()
.HasMaxLength(100)
.HasColumnName("Address_FirstLine");
this.Property(t => t.Address.ZipCode)
.IsRequired()
.HasMaxLength(20).HasColumnName("Address_Zip");
this.Property(t => t.Address.Contry)
.IsRequired()
.HasMaxLength(100).HasColumnName("Address_Contry");
this.Property(t => t.Address.City)
.IsRequired()
.HasMaxLength(100).HasColumnName("Address_Town");
this.Property(t => t.Id);
// Table & Column Mappings
this.ToTable("Identities_Member");
this.Property(t => t.FirstName).HasColumnName("FirstName");
this.Property(t => t.LastName).HasColumnName("LastName");
this.Property(t => t.Email).HasColumnName("Email");
this.Property(t => t.Id).HasColumnName("Id");
// Relationships
}
}