2

我一直很难尝试调试此异常：Exception in thread "AWT-EventQueue-0" java.lang.ArrayIndexOutOfBoundsException: 1

这是我的代码

package com.Homework.Table;

import java.awt.BorderLayout;
import java.awt.Container;
import javax.swing.JFrame;
import javax.swing.JScrollPane;
import javax.swing.JTable;

public class ArrayTable  {
    static String [][] records;

    public static void main(String [] args)
    {
        String [] columns= { "col1", "col2", "col3","col4" };
        String array ="A&B&1&May 8 2011 12:17AM;;E&D&5&May 8 2011 12:43AM;;F&G&5&May 8 2011 7:06AM;;H&I&1&May 14 2011 11:57PM";
        records=to2dim (array ,";;","&");
        Object rows[][] =records;
        JFrame f = new JFrame("JTable Sample");
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        Container content = f.getContentPane();
        JTable table = new JTable(rows, columns);
        JScrollPane scrollPane = new JScrollPane(table);
        content.add(scrollPane, BorderLayout.CENTER);
        f.setSize(300, 200);
        f.setVisible(true);
    }

    public static String [][] to2dim (String source , String outerdelim, String innerdelim) {
        String [][] result = new String [source.replaceAll ("[^" + outerdelim + "]", "").length () + 1][]; 
        int count = 0;
        for (String line : source.split ("[" + outerdelim + "]"))
        {
            result [count++] = line.split (innerdelim);
        }
        return result;
    }
}

这是我得到的回应

 Exception in thread "AWT-EventQueue-0" java.lang.ArrayIndexOutOfBoundsException: 1
at javax.swing.JTable$1.getValueAt(Unknown Source)
at javax.swing.JTable.getValueAt(Unknown Source)
at javax.swing.JTable.prepareRenderer(Unknown Source)
at javax.swing.plaf.basic.BasicTableUI.paintCell(Unknown Source)
at javax.swing.plaf.basic.BasicTableUI.paintCells(Unknown Source)
at javax.swing.plaf.basic.BasicTableUI.paint(Unknown Source)
at javax.swing.plaf.ComponentUI.update(Unknown Source)
at javax.swing.JComponent.paintComponent(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JViewport.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JLayeredPane.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paintToOffscreen(Unknown Source)
at javax.swing.BufferStrategyPaintManager.paint(Unknown Source)
at javax.swing.RepaintManager.paint(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at java.awt.GraphicsCallback$PaintCallback.run(Unknown Source)
at sun.awt.SunGraphicsCallback.runOneComponent(Unknown Source)
at sun.awt.SunGraphicsCallback.runComponents(Unknown Source)
at java.awt.Container.paint(Unknown Source)
at javax.swing.RepaintManager.paintDirtyRegions(Unknown Source)
at javax.swing.RepaintManager.paintDirtyRegions(Unknown Source)
at javax.swing.RepaintManager.seqPaintDirtyRegions(Unknown Source)
at javax.swing.SystemEventQueueUtilities$ComponentWorkRequest.run(Unknown Source)
at java.awt.event.InvocationEvent.dispatch(Unknown Source)
at java.awt.EventQueue.dispatchEvent(Unknown Source)
at java.awt.EventDispatchThread.pumpOneEventForFilters(Unknown Source)
at java.awt.EventDispatchThread.pumpEventsForFilter(Unknown Source)
at java.awt.EventDispatchThread.pumpEventsForHierarchy(Unknown Source)
at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
at java.awt.EventDispatchThread.run(Unknown Source)

帮我。

4

2 回答 2

2 
import java.awt.BorderLayout;
import java.awt.Container;
import javax.swing.JFrame;
import javax.swing.JScrollPane;
import javax.swing.JTable;
import java.util.Arrays;
public class ArrayTable  {
    static String [][] records;

    public static void main(String [] args)
    {
        String [] columns= { "col1", "col2", "col3","col4" };
        String array ="A&B&1&May 8 2011 12:17AM;;E&D&5&May 8 2011 12:43AM;;F&G&5&May 8 2011 7:06AM;;H&I&1&May 14 2011 11:57PM";
        records=to2dim (array ,";;","&");
        Object rows[][] =records;
        JFrame f = new JFrame("JTable Sample");
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        Container content = f.getContentPane();
        JTable table = new JTable(rows, columns);
        JScrollPane scrollPane = new JScrollPane(table);
        content.add(scrollPane, BorderLayout.CENTER);
        f.setSize(300, 200);
        f.setVisible(true);
    }

    public static String [][] to2dim (String source , String outerdelim, String innerdelim) {

        String [][] result = new String [(source.split (outerdelim)).length][];
        int count = 0;

        System.out.println("result len "+result.length);
        for (String line : source.split (outerdelim ))
            {
                result [count++] = line.split (innerdelim);
            }

        System.out.println(Arrays.deepToString(result));
        return result;
    }
}

这应该适合你。[;;]仅匹配单个字符，因此基于此的拆分将在两个连续;的 . 所以应该改成 just ;;。

于 2012-09-27T10:25:14.723 回答
1

您在第 2、第 4 和第 6 行中只有一列。应该是 4 列。

于 2012-09-27T10:21:53.663 回答