13

对于某些整数类型，即使浮点值远远超出整数的可表示范围，我如何才能找到最接近浮点类型的某个值的值。

或者更准确地说：

设F为浮点类型（可能是float、double或long double）。设为I整数类型。

假设两者F和I都有有效的专业化std::numeric_limits<>。

给定一个可表示的值F，并且只使用 C++03，我怎样才能找到最接近的可表示值I？

我追求的是一种纯粹、高效和线程安全的解决方案，除了 C++03 所保证的之外，它对平台没有任何假设。

如果不存在这样的解决方案，是否可以使用 C99/C++11 的新特性找到一个解决方案？

由于报告域错误的方式不平凡，使用lround()C99 似乎存在问题。能否以可移植和线程安全的方式捕获这些域错误？

注意：我知道 Boost 可能通过它的boost::numerics::converter<>模板提供了一个解决方案，但是由于它的高度复杂性和冗长，我无法从中提取要领，因此我无法检查他们的解决方案是否使超出 C++03 的假设。

以下天真的方法失败了，因为I(f)当 的整数部分f不是 的可表示值时，C++03 未定义 的结果I。

template<class I, class F> I closest_int(F f)
{
  return I(f);
}

然后考虑以下方法：

template<class I, class F> I closest_int(F f)
{
  if (f < std::numeric_limits<I>::min()) return std::numeric_limits<I>::min();
  if (std::numeric_limits<I>::max() < f) return std::numeric_limits<I>::max();
  return I(f);
}

F(std::numeric_limits<I>::min())这也失败了，因为和的组成部分F(std::numeric_limits<I>::max())可能仍然无法在 中表示I。

最后考虑这第三种方法，它也失败了：

template<class I, class F> I closest_int(F f)
{
  if (f <= std::numeric_limits<I>::min()) return std::numeric_limits<I>::min();
  if (std::numeric_limits<I>::max() <= f) return std::numeric_limits<I>::max();
  return I(f);
}

这个时间I(f)总是会有一个明确定义的结果，但是，因为F(std::numeric_limits<I>::max())可能比 小得多std::numeric_limits<I>::max()，所以我们可能会返回std::numeric_limits<I>::max()一个浮点值，它是低于 的多个整数值std::numeric_limits<I>::max()。

请注意，之所以会出现所有麻烦，是因为未定义转换是F(i)向上舍入还是向下舍入到最接近的可表示浮点值。

以下是 C++03（4.9 浮点整数转换）的相关部分：

整数类型或枚举类型的右值可以转换为浮点类型的右值。如果可能，结果是准确的。否则，它是下一个较低或较高可表示值的实现定义选择。

4

1 回答 1

3

对于 radix-2（二进制）浮点类型和大于等于 64 位的整数类型，我有一个实用的解决方案。见下文。评论应该清楚。输出如下。

// file: f2i.cpp
//
// compiled with MinGW x86 (gcc version 4.6.2) as:
//   g++ -Wall -O2 -std=c++03 f2i.cpp -o f2i.exe
#include <iostream>
#include <iomanip>
#include <limits>

using namespace std;

template<class I, class F> I truncAndCap(F f)
{
/*
  This function converts (by truncating the
  fractional part) the floating-point value f (of type F)
  into an integer value (of type I), avoiding undefined
  behavior by returning std::numeric_limits<I>::min() and
  std::numeric_limits<I>::max() when f is too small or
  too big to be converted to type I directly.

  2 problems:
  - F may fail to convert to I,
    which is undefined behavior and we want to avoid that.
  - I may not convert exactly into F
    - Direct I & F comparison fails because of I to F promotion,
      which can be inexact.

  This solution is for the most practical case when I and F
  are radix-2 (binary) integer and floating-point types.
*/
  int Idigits = numeric_limits<I>::digits;
  int Isigned = numeric_limits<I>::is_signed;

/*
  Calculate cutOffMax = 2 ^ std::numeric_limits<I>::digits
  (where ^ denotes exponentiation) as a value of type F.

  We assume that F is a radix-2 (binary) floating-point type AND
  it has a big enough exponent part to hold the value of
  std::numeric_limits<I>::digits.

  FLT_MAX_10_EXP/DBL_MAX_10_EXP/LDBL_MAX_10_EXP >= 37
  (guaranteed per C++ standard from 2003/C standard from 1999)
  corresponds to log2(1e37) ~= 122, so the type I can contain
  up to 122 bits. In practice, integers longer than 64 bits
  are extremely rare (if existent at all), especially on old systems
  of the 2003 C++ standard's time.
*/
  const F cutOffMax = F(I(1) << Idigits / 2) * F(I(1) << (Idigits / 2 + Idigits % 2));

  if (f >= cutOffMax)
    return numeric_limits<I>::max();

/*
  Calculate cutOffMin = - 2 ^ std::numeric_limits<I>::digits
  (where ^ denotes exponentiation) as a value of type F for
  signed I's OR cutOffMin = 0 for unsigned I's in a similar fashion.
*/
  const F cutOffMin = Isigned ? -F(I(1) << Idigits / 2) * F(I(1) << (Idigits / 2 + Idigits % 2)) : 0;

  if (f <= cutOffMin)
    return numeric_limits<I>::min();

/*
  Mathematically, we may still have a little problem (2 cases):
    cutOffMin < f < std::numeric_limits<I>::min()
    srd::numeric_limits<I>::max() < f < cutOffMax

  These cases are only possible when f isn't a whole number, when
  it's either std::numeric_limits<I>::min() - value in the range (0,1)
  or std::numeric_limits<I>::max() + value in the range (0,1).

  We can ignore this altogether because converting f to type I is
  guaranteed to truncate the fractional part off, and therefore
  I(f) will always be in the range
  [std::numeric_limits<I>::min(), std::numeric_limits<I>::max()].
*/

  return I(f);
}

template<class I, class F> void test(const char* msg, F f)
{
  I i = truncAndCap<I,F>(f);
  cout <<
    msg <<
    setiosflags(ios_base::showpos) <<
    setw(14) << setprecision(12) <<
    f << " -> " <<
    i <<
    resetiosflags(ios_base::showpos) <<
    endl;
}

#define TEST(I,F,VAL) \
  test<I,F>(#F " -> " #I ": ", VAL);

int main()
{
  TEST(short, float,     -1.75f);
  TEST(short, float,     -1.25f);
  TEST(short, float,     +0.00f);
  TEST(short, float,     +1.25f);
  TEST(short, float,     +1.75f);

  TEST(short, float, -32769.00f);
  TEST(short, float, -32768.50f);
  TEST(short, float, -32768.00f);
  TEST(short, float, -32767.75f);
  TEST(short, float, -32767.25f);
  TEST(short, float, -32767.00f);
  TEST(short, float, -32766.00f);
  TEST(short, float, +32766.00f);
  TEST(short, float, +32767.00f);
  TEST(short, float, +32767.25f);
  TEST(short, float, +32767.75f);
  TEST(short, float, +32768.00f);
  TEST(short, float, +32768.50f);
  TEST(short, float, +32769.00f);

  TEST(int, float, -2147483904.00f);
  TEST(int, float, -2147483648.00f);
  TEST(int, float, -16777218.00f);
  TEST(int, float, -16777216.00f);
  TEST(int, float, -16777215.00f);
  TEST(int, float, +16777215.00f);
  TEST(int, float, +16777216.00f);
  TEST(int, float, +16777218.00f);
  TEST(int, float, +2147483648.00f);
  TEST(int, float, +2147483904.00f);

  TEST(int, double, -2147483649.00);
  TEST(int, double, -2147483648.00);
  TEST(int, double, -2147483647.75);
  TEST(int, double, -2147483647.25);
  TEST(int, double, -2147483647.00);
  TEST(int, double, +2147483647.00);
  TEST(int, double, +2147483647.25);
  TEST(int, double, +2147483647.75);
  TEST(int, double, +2147483648.00);
  TEST(int, double, +2147483649.00);

  TEST(unsigned, double,          -1.00);
  TEST(unsigned, double,          +1.00);
  TEST(unsigned, double, +4294967295.00);
  TEST(unsigned, double, +4294967295.25);
  TEST(unsigned, double, +4294967295.75);
  TEST(unsigned, double, +4294967296.00);
  TEST(unsigned, double, +4294967297.00);

  return 0;
}

输出（ideone打印与我的 PC 相同）：

float -> short:          -1.75 -> -1
float -> short:          -1.25 -> -1
float -> short:             +0 -> +0
float -> short:          +1.25 -> +1
float -> short:          +1.75 -> +1
float -> short:         -32769 -> -32768
float -> short:       -32768.5 -> -32768
float -> short:         -32768 -> -32768
float -> short:      -32767.75 -> -32767
float -> short:      -32767.25 -> -32767
float -> short:         -32767 -> -32767
float -> short:         -32766 -> -32766
float -> short:         +32766 -> +32766
float -> short:         +32767 -> +32767
float -> short:      +32767.25 -> +32767
float -> short:      +32767.75 -> +32767
float -> short:         +32768 -> +32767
float -> short:       +32768.5 -> +32767
float -> short:         +32769 -> +32767
float -> int:    -2147483904 -> -2147483648
float -> int:    -2147483648 -> -2147483648
float -> int:      -16777218 -> -16777218
float -> int:      -16777216 -> -16777216
float -> int:      -16777215 -> -16777215
float -> int:      +16777215 -> +16777215
float -> int:      +16777216 -> +16777216
float -> int:      +16777218 -> +16777218
float -> int:    +2147483648 -> +2147483647
float -> int:    +2147483904 -> +2147483647
double -> int:    -2147483649 -> -2147483648
double -> int:    -2147483648 -> -2147483648
double -> int: -2147483647.75 -> -2147483647
double -> int: -2147483647.25 -> -2147483647
double -> int:    -2147483647 -> -2147483647
double -> int:    +2147483647 -> +2147483647
double -> int: +2147483647.25 -> +2147483647
double -> int: +2147483647.75 -> +2147483647
double -> int:    +2147483648 -> +2147483647
double -> int:    +2147483649 -> +2147483647
double -> unsigned:             -1 -> 0
double -> unsigned:             +1 -> 1
double -> unsigned:    +4294967295 -> 4294967295
double -> unsigned: +4294967295.25 -> 4294967295
double -> unsigned: +4294967295.75 -> 4294967295
double -> unsigned:    +4294967296 -> 4294967295
double -> unsigned:    +4294967297 -> 4294967295
于 2012-09-27T04:43:50.170 回答