python - 饼图中的matplotlib mouseclick事件

Question

matplotlib 和 Python 中有没有办法返回在饼图中单击的值/标签。例如，如果用户点击饼图的条形图 A，返回值 A。如果用户点击 B 饼图的条形图 B，则返回值 B。

Answer 1

from matplotlib import pyplot as plt
# make a square figure and axes
plt.figure(figsize=(6,6))
ax = plt.axes([0.1, 0.1, 0.8, 0.8])

labels = 'Frogs', 'Hogs', 'Dogs', 'Logs'
fracs = [15,30,45, 10]

explode=(0, 0.05, 0, 0)
p = plt.pie(fracs, explode=explode, labels=labels, autopct='%1.1f%%', shadow=True)
plt.title('Raining Hogs and Dogs', bbox={'facecolor':'0.8', 'pad':5})

w = p[0][0]
plt.show() 

class PieEventHandler:
    def __init__(self,p):
        self.p = p
        self.fig = p[0].figure
        self.ax = p[0].axes
        self.fig.canvas.mpl_connect('button_press_event', self.onpress)

    def onpress(self, event):
        if event.inaxes!=self.ax:
            return

        for w in self.p:
            (hit,_) = w.contains(event)
            if hit:
                print w.get_label()


handler = PieEventHandler(p[0])

参考：

matplotlib的imshow中的颜色值？

http://matplotlib.org/examples/pylab_examples/pie_demo.html

Answer 2

:)

import matplotlib.pyplot as plt

def main():
    # Make an example pie plot
    fig = plt.figure()
    ax = fig.add_subplot(111)

    labels = ['Apple', 'Mango', 'Orange']
    wedges, plt_labels = ax.pie([20, 40, 60], labels=labels)
    ax.axis('equal')

    make_picker(fig, wedges)
    plt.show()

def make_picker(fig, wedges):

    def onclick(event):
        wedge = event.artist
        label = wedge.get_label()
        print label

# Make wedges selectable
    for wedge in wedges:
        wedge.set_picker(True)

    fig.canvas.mpl_connect('pick_event', onclick)

if __name__ == '__main__':
    main()