python - 在不同的行中打印每个列表元素，并在每个元素之前重复一个字符串 Python

Question

我想在列表的每个元素前面打印一个字符串，然后在新行中打印：

例子：

    test = ["aaa", "bee", "cee"]
    print("hello, %s" % "\n".join(storageVolume))

我从中得到的是：

    hello, aaa
    bee
    cee

我想要的是：

    hello, aaa
    hello, bee
    hello, cee

任何帮助表示赞赏。

Answer 1

for x in test:
    print "Hello, {0}".format(x) 

Answer 2

In [10]: test = ["aaa", "bee", "cee"]

In [11]: print "\n".join("hello, "+x for x in test)
hello, aaa
hello, bee
hello, cee

或者：

In [13]: print "\n".join("hello,  {0}".format(x) for x in test)
hello,  aaa
hello,  bee
hello,  cee

Answer 3

In [51]: test = ["aaa", "bee", "cee"]

In [52]: for elem in test:
   ....:     print "hello,", elem
   ....:
hello, aaa
hello, bee
hello, cee

Answer 4

     for i in range(len(test)):
        print "Hello, "+(test[i]);