我在 ORACLE SQL 中有以下查询:
Select
Trunc(Cs.Create_Dtime),
Count(Case When Cs.Cs_Listing_Id Like '99999999%' Then (Cs.Player_Id) End) As Sp_Dau,
Count(Case When Cs.Cs_Listing_Id Not Like '99999999%' Then (Cs.Player_Id) End) As Cs_Dau
From
Player_Chkin_Cs Cs
Where
Trunc(Cs.Create_Dtime) >= To_Date('2012-Jan-01','yyyy-mon-dd')
Group By Trunc(Cs.Create_Dtime)
Order By 1 ASC
我在每个计数的“case”之前添加了“Distinct”。我只是想确保这在每种情况下只返回所有不同的 player_Ids。有人可以确认吗?谢谢!这是最终的查询:
Select
Trunc(Cs.Create_Dtime),
Count(Distinct Case When Cs.Cs_Listing_Id Like '99999999%' Then (Cs.Player_Id) End) As Sp_Dau,
Count(Distinct Case When Cs.Cs_Listing_Id Not Like '99999999%' Then (Cs.Player_Id) End) As Cs_Dau
From
Player_Chkin_Cs Cs
Where
Trunc(Cs.Create_Dtime) >= To_Date('2012-Jan-01','yyyy-mon-dd')
Group By Trunc(Cs.Create_Dtime)
Order By 1 ASC;