1

好的，非常简单的任务，我只是不擅长 PHP。

我有一个页面，我想在其中使用样式列表列出一些员工。这是页面 - http://www.themontessoripeople.co.uk/montesori/?post_type=people

我下载了一个“自定义内容类型”插件并添加了“人”的内容类型并添加了相应的字段。现在我想过滤我通过名为“层次结构”的自定义字段添加的帖子。

这是我希望页面显示的方式 - http://i47.tinypic.com/oqymwh.jpg

自定义字段“hierarchy”包含“management”、“babies_room”和“toddlers_room”的房间变量。

如何修改下面的代码以按其中包含的值过滤帖子<?php print_custom_field('hierarchy'); ?>？

<?php $col = 1; ?>      
    <?php if (have_posts()) : ?>        
        <?php while (have_posts()) : the_post(); ?>         
            <?php if ($col == 1) echo "<div class=\"row\">"; ?>

                <div class="post col<?php echo $col;?>" id="post-<?php the_ID(); ?>">

                            <div class="people-spacer">

                                <div class="people"><a class="animate" >
                                <div class="bio">
                                <p class="titles"><?php the_title(); ?><br/>
                                <span class="job"> <?php print_custom_field('job'); ?></span> </p><br />
                                </div>
                                <img src="<?php print_custom_field('staff_image:to_image_src'); ?>" width="160" height="160" alt="<?php the_title(); ?>-image" />
                                </div>
                                <div class="people-link-edit"><?php edit_post_link('Edit Post', ''); ?></div>
                            </div>
                </div>

            <?php if ($col == 1) echo "</div>"; (($col==1) ? $col=2 : $col=2); ?>   
        <?php endwhile; ?>

谢谢，本。

这是显示两组过滤结果以供参考的工作代码 -

<?php $col = 1; ?>
<?php if (have_posts()) : ?>


<div class="text-box">

<h2>Management</h2>
<?php while (have_posts()) : the_post(); ?>
<?php if (get_custom_field('hierarchy') != "management") continue; ?>

<?php if ($col == 1) echo "<div class=\"row\">"; ?>
<div class="post col<?php echo $col;?>" id="post-<?php the_ID(); ?>">
 <div class="people-spacer">
  <div class="people"><a class="animate" >
   <div class="bio">
    <p class="titles">
     <?php the_title(); ?>
     <br/>
     <span class="job"> <?php print_custom_field('job'); ?></span> </p>
    <br />
   </div>
   <img src="<?php print_custom_field('staff_image:to_image_src'); ?>" width="160" height="160" alt="<?php the_title(); ?>-image" /> </div>
  <div class="people-link-edit">
   <?php edit_post_link('Edit Post', ''); ?>
  </div>
 </div>
</div>
<?php if ($col == 1) echo "</div>"; (($col==1) ? $col=2 : $col=2); ?>
<?php endwhile; ?>

</div><!-- close text box -->


<div class="text-box">

<h2>Babies Room</h2>

<?php while (have_posts()) : the_post(); ?>
<?php if (get_custom_field('hierarchy') != "babies_room") continue; ?>

<?php if ($col == 1) echo "<div class=\"row\">"; ?>
<div class="post col<?php echo $col;?>" id="post-<?php the_ID(); ?>">
 <div class="people-spacer">
  <div class="people"><a class="animate" >
   <div class="bio">
    <p class="titles">
     <?php the_title(); ?>
     <br/>
     <span class="job"> <?php print_custom_field('job'); ?></span> </p>
    <br />
   </div>
   <img src="<?php print_custom_field('staff_image:to_image_src'); ?>" width="160" height="160" alt="<?php the_title(); ?>-image" /> </div>
  <div class="people-link-edit">
   <?php edit_post_link('Edit Post', ''); ?>
  </div>
 </div>
</div>
<?php if ($col == 1) echo "</div>"; (($col==1) ? $col=2 : $col=2); ?>
<?php endwhile; ?>

</div><!-- close text box -->
4

2 回答 2

1

我已经简化了你的代码。过滤器也被添加：

<?php
    $col = 1;
    while (have_posts())
    {
        the_post();
        if ($col == 1) echo "<div class=\"row\">";

        // filter
        $hierarchy = get_custom_field('hierarchy');
        // if it does not match continue (skip)
        if ($hierarchy != "boss") continue;
        // if it matches continue (skip)
        //if ($hierarchy == "notboss") continue;

        // needed fields
        $id = the_ID();
        $job = get_custom_field('job');
        $title = the_title();
        $img = get_custom_field('staff_image:to_image_src');
        $edit = edit_post_link('Edit Post', '');

        echo <<< END
                <div class="post col$col" id="post-$id">
                    <div class="people-spacer">
                        <div class="people"><a class="animate" >
                        <div class="bio">
                        <p class="titles">$title<br/>
                        <span class="job">$job</span> </p><br />
                        </div>
                        <img src="$img" width="160" height="160" alt="$title-image" />
                        </div>
                        <div class="people-link-edit">$edit</div>
                    </div>
                </div>
END;

        if ($col == 1) echo "</div>";
        (($col==1) ? $col=2 : $col=2);
    }
?>

编辑：get_custom_field 而不是 print_custom_field。

于 2012-09-25T23:41:06.923 回答
0

您可以定义查询参数query_posts($args)- 看看query_posts。也许你可以试试get_posts

于 2012-09-25T23:41:35.663 回答