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我正在编写一个迷宫程序。用户由字符“P”表示，我需要能够找到该字符以便为我的移动命令分配值。我对如何在迷宫中找到“P”感到困惑。

public static void main(String[] args) throws Exception{

    //Display the maze
    char treasureMaze[][] = {{'P','.','X','X','.'},{'.','X','.','.','.'},{'.','.','.','X','.'},{'X','X','T','.','.'},{'.','.','X','.','.'}}; 
    display(treasureMaze);


    //Give Move Options
    options();

    //Get Users Decision
    Scanner moveChoice = new Scanner(System.in);
    int choice = moveChoice.nextInt();

    if(choice == 1){
        System.out.println("You chose to Move up");
    }
    else if(choice == 2){
        System.out.println("You chose to Move down");
    }
    else if(choice == 3){
        System.out.println("You chose to Move left");
    }
    else if(choice == 4){
        System.out.println("you chose to Move right");
    }
    else{
        return;
    }


    //Move the Player
    //Move Up
    if(choice == 1){
        if(treasureMaze[0-1][0] == '.'){
            treasureMaze[0-1][0] = 'P';
            treasureMaze[0-1][0] = '.';
        }
        else if(treasureMaze[0-1][0] == 'T'){
            System.out.println("Congratulations you won!");
        }
        else{
            System.out.println("Cannot move there! Try something else");
        }
    }

    //Move Down
    else if(choice == 2){
        if(treasureMaze[0+1][0] == '.'){
            treasureMaze[0+1][0] = 'P';
            treasureMaze[0][0] = '.';
        }               
        else if(treasureMaze[0+1][0] == 'T'){
            System.out.println("Congratulations you won!");
        }
        else{                   
            System.out.println("Cannot move there! Try something else");
            }
            }

    //Move Left
    else if(choice == 3){
        if(treasureMaze[0][0-1] == '.'){
            treasureMaze[0][0-1] = 'P';
            treasureMaze[0][0] = '.';
        }
        else if(treasureMaze[0][0-1] == 'T'){
            System.out.println("Congratulations you won!");
        }
        else{
            System.out.println("Cannot move there! Try something else");
        }
    }

    //Move Right
    else if(choice == 4){
    if(treasureMaze[0][0+1] == '.'){
        treasureMaze[0][0+1] = 'P';
        treasureMaze[0][0] = '.';
    }
    else if(treasureMaze[0][0+1] == 'T'){
        System.out.println("Congratulations you won!");
    }
    else{
        System.out.println("Cannot move there! Try something else");
    }
    }
    else{
        return;
    }
    display(treasureMaze);
    options();
}



//Display Object: prints out the maze for the user
public static void display(char x[][]){
    for(int row = 0; row < x.length; row++){
        for(int column = 0; column < x[row].length; column++){
            System.out.print(x[row][column] + "\t");
        }
        System.out.println();
    }
}

//Options Object: gives the options menu to the user
 static void options(){
     System.out.println("You may:");
        System.out.println("\t1) Move up");
        System.out.println("\t2) Move down");
        System.out.println("\t3) Move left");
        System.out.println("\t4) Move right");
        System.out.println("\t0) Quit");

}

我已将其设置为将“P”从其起始位置移动，但不知道如何定位它以进行下一次运行。有任何想法吗？

4

2 回答 2

3

我建议跟踪当前位置，这样您就不必找到它。为玩家的水平和垂直位置声明两个变量。在设置棋盘时初始化它们（看起来应该是 (0, 0)），并在玩家移动时更新它们。

于 2012-09-25T19:49:00.847 回答
1

Ted 的回答可能最适合您当前的程序设置方式。

作为替代方案，您可以用树替换 2D 数组。这种方法的一个附带好处是您不必担心数组索引超出范围。每个房间都会引用它所连接的其他房间，可能只是无效的方向null，您可以保留对玩家当前房间的引用。

于 2012-09-25T20:02:42.640 回答