-1

我有以下脚本，但找不到错误。有人帮我吗？

具体来说，我将一个大文件拆分为不同的文件，然后压缩任何文件，移动它并通过 ftp 重命名目标文件名发送。

有些东西不起作用:(

在线：放 ${file} ${7}.T${j}(+1)

我尝试用（+1）结尾的新文件名重命名文件

亲切的问候

#!/bin/bash

# configuration stuff

# ${1} absolute path file
# ${2} num_files
# ${3} output_filename
# ${4} ipMainframe ip to put files
# ${5} FTP username
# ${6} FTP password
# ${7} destination filename

if [ ! $# == 7 ]; then
        #number of parameter different of two
        echo "Number of parameter incorrect"
        echo "Command use: LLP_split_gzip_sendFTPandTrigger.sh absolute_path_file number_of_pieces output_filename ipMainframe userFTP pwdFTP destinationFilename"
        exit 1
fi

if [ -f ${1} ]; then
        # If file exists
        if [[ ${2} =~ ^[\-0-9]+$ ]] && (( ${2} > 0)); then
                # if number of pieces is an integer > 0
                #Remove old files
                echo "home directory = $HOME"
                CMD=`rm -f '"$HOME"/"$3"*'`
                if [ $? != 0 ]; then
                        echo "Impossible to remove old files $home/llp_tmp* $home/"$3"* in home directory"
                        echo $CMD
                fi
                # Calculate line for every file splitted
                total_lines=$(cat ${1} | wc -l)
                ((lines_per_file = (total_lines + ${2} - 1) / ${2}))
                # Split the actual file, maintaining lines.
                CMD=`split -l "$lines_per_file" "$1" "$HOME"/llp_tmp`
                if [ $? != 0 ]; then
                        echo "SPLITTING FILE ERROR: problem to split file."
                        echo $CMD
                        exit 3
                fi
                #For every file splitted rename and zip it
                i=1
                for file in $HOME/llp_tmp*; do
                        CMD=`mv "$file" "$3"."$i"`
                        if [ $? != 0 ]; then
                                echo "Impossible to rename file"
                                echo $CMD
                                exit 5
                        fi
                        CMD=`gzip "$3"."$i"`
                        if [ $? != 0 ]; then
                                echo "Impossible to compress file $3.$i"
                                echo $CMD
                                exit 6
                        fi
                        i=`expr $i + 1`
                done
                ftp -n ${4} << EOF

                j=1
                user ${5} ${6}
                for file in $3.*; do
                        put ${file} ${7}.T${j}(+1)
                        j=`expr $j + 1`
                done
                quit
        else
                echo "number of pieces second parameter must be more than 0."
                exit 2
        fi
else
        echo "absolute path first paramater doesnt exist"
        exit 1
fi
exit 0
4

2 回答 2

2

您没有终止您的此处文档。当我运行你的脚本时，我得到：

gash.sh: line 72: warning: here-document at line 54 delimited by end-of-file (wanted `EOF')
gash.sh: line 73: syntax error: unexpected end of file

ftp -n ${4} << EOF是问题。你的文件在哪里？

警告说明了一切，您没有EOF标记。请注意，这不能缩进！EOF必须在“第0 列”并且没有尾随字符，包括空格。

编辑：您似乎想在单个 FTP 会话中使用程序构造——我不知道在 Bash 中这样做的方法。Perl 有一个易于使用的 FTP 模块，您可以在其中执行此操作，简单示例：

use strict;
use Net::FTP;

my $ftp = Net::FTP->new ("hostname");
$ftp->login ("username", "password");
$ftp->binary ();

for my $file (glob("$ENV{HOME}/llp_tmp*")) {

    $ftp->put ($file); 
}
$ftp->quit();
于 2012-09-25T11:59:40.053 回答
0

你不需要括号+1。

将其更改为：

put "${file}" "${7}.T${j}+1"

引用变量是一种很好的做法。

另一个提示：j=`expr $j + 1`您可以简单地使用. 而不是((j++)).

于 2012-09-25T10:38:29.250 回答