我已经为使用多个表的显示输出创建了编码,所以我使用了 Join 函数。但我想添加一个额外的列来插入注释。当我点击保存按钮时,笔记确实保存在数据库中。
- 这是 JOIN 查询的编码。
if(isset($_POST['btnsearch']))
{
    $searchKul=$_POST['txtkul'];
    $searchSem=$_POST['txtsem'];
    if( $searchKul && $searchSem!= NULL)
    {
            $queryKul       =  "SELECT DISTINCT  _kursus.namakur_bm, _kursus.kodkursus, _kulliyah.kod_kul, kur_twr.sesi_sem, exm_penilaian.kod_skema                                                                                                        
                                FROM _kulliyah
                                JOIN _program ON _kulliyah.kod_kul = _program.kod_kul
                                JOIN kur_twr ON _program.kod_prog = kur_twr.kod_prog
                                JOIN _kursus ON kur_twr.kodkursus = _kursus.kodkursus
                                JOIN exm_penilaian ON _kursus.kodkursus = exm_penilaian.kodkursus
                                WHERE _kulliyah.kod_kul LIKE '%$searchKul%'
                                AND kur_twr.sesi_sem LIKE '%$searchSem%'
                                ORDER BY kodkursus";
            $rsKul               = mysql_query($queryKul);
            $row_rsKul           = mysql_fetch_assoc($rsKul);
            $totalRows_rsKul     = mysql_num_rows($rsKul);
这是用于编码说明
if(isset($_POST['btnsave'])) { $txtadd = $_POST['txtadd'];
$result=mysql_query("INSERT INTO _kursus(remark) VALUES('$txtadd')"); if($result) { echo ("<script language='JavaScript'>alert('Succesfully INSERT data!');</script> <script language='JavaScript'>window.location='kul7.php';</script>"); } else { echo 'PLEASE ENTER AGAIN'; } }?> <form action="" method="POST"> <input type="text" name="txtadd"/><input type="submit" name="btnsave" value="SAVE"/> </form> <?php "</td>"; echo "</tr>"; } while($row_rsKul = mysql_fetch_assoc($rsKul)); { echo "</table></center>"; } mysql_close(); } }
$result=mysql_query("INSERT INTO _kursus(remark) VALUES('$txtadd')");
上面的查询似乎不起作用。我无法将数据保存到数据库。当我单击“保存”按钮时,什么也没有发生..