0

我在这里有一个名为 tb_user 的动态表，其列 region_id 和 Institute_id 并且两个 id 都是另一个表 tb_region（具有列 region_name 和 region_id）和 tb_institute（列 institut_id 和 Institute_name）的主键。我想查看 region_name 和 Institute_name 而不是 ID。

我用过这个 php 脚本

<?php echo $row_institute['institution_name']; ?>

并查询以收集 tb_institute 的数据

mysql_select_db($database_connection_ched, $connection_ched);
$query_institution = "SELECT institute_id, institute_name FROM   tb_institute";
$institution = mysql_query($query_institution, $connection_ched) or die(mysql_error());
$row_institution = mysql_fetch_assoc($institution);
$totalRows_institution = mysql_num_rows($institution);

但似乎没有显示正确的id名称。

我用来收集数据的查询：

mysql_select_db($database_connection_ched, $connection_ched);
$query_notification = sprintf("SELECT * FROM tb_user WHERE status = 'inactive' ORDER BY     date_register ASC", GetSQLValueString($colname_notification, "text"));
$query_limit_notification = sprintf("%s LIMIT %d, %d", $query_notification,     $startRow_notification, $maxRows_notification);
$notification = mysql_query($query_limit_notification, $connection_ched) or die(mysql_error());
$row_notification = mysql_fetch_assoc($notification);


if (isset($_GET['totalRows_notification'])) {
  $totalRows_notification = $_GET['totalRows_notification'];
} else {
  $all_notification = mysql_query($query_notification);
  $totalRows_notification = mysql_num_rows($all_notification);
}
$totalPages_notification = ceil($totalRows_notification/$maxRows_notification)-1;
4

1 回答 1

0 
$row_institution['institute_name']

代替

$row_institute['institution_name']
于 2012-09-25T03:28:19.513 回答