2

我正在尝试阅读https://d3ca01230439ce08d4aab0c61810af23:bla@mycon.mycompany.com/recordings.atom

使用罗马，但它给了我错误

   INFO: Illegal access: this web application instance has been stopped already.  Could not load org.bouncycastle.jcajce.provider.symmetric.AES$ECB.  The eventual following stack trace is caused by an error thrown for debugging purposes as well as to attempt to terminate the thread which caused the illegal access, and has no functional impact.

和

   Server returned HTTP response code: 401 for URL: https://d3ca01230439ce08d4aab0c61810af23:bla@mycon.mycompany.com/recordings.atom .

我正在这样做

    URL url =  new URL("https://d3ca01230439ce08d4aab0c61810af23:bla@mycon.mycompany.com/recordings.atom ");

    try {
    SyndFeedInput input = new SyndFeedInput();

        SyndFeed feed = input.build(new XmlReader(url));

        System.out.println("Feed Author:"+feed.getAuthor());

        for(Object entries: feed.getEntries()){

            SyndEntry entry = (SyndEntry) entries;

            System.out.println("title :"+entry.getTitle());
            System.out.println("description : "+entry.getDescription());

        }


    } catch (IllegalArgumentException | FeedException | IOException e) {
        e.printStackTrace();
    }

我需要将用户名密码放在某处吗？

更新

这是我做过的

  URL url =  new URL("https://d3ca01230439ce08d4aab0c61810af23:bla@mycon.mycompany.com/recordings.atom");

    HttpURLConnection httpcon = (HttpURLConnection)url.openConnection();

    String encoding = new sun.misc.BASE64Encoder().encode("username:pass".getBytes());

    httpcon.setRequestProperty  ("Authorization", "Basic " + encoding);
4

3 回答 3

7

当我从浏览器中点击该 URL 时，它会要求进行基本身份验证。您可以使用 ROM 执行此操作：

URL feedUrl = new URL(feed)
HttpURLConnection httpcon = (HttpURLConnection)feedUrl.openConnection();
String encoding = new sun.misc.BASE64Encoder().encode("username:password".getBytes());
httpcon.setRequestProperty  ("Authorization", "Basic " + encoding);
SyndFeedInput input = new SyndFeedInput();
SyndFeed feed = input.build(new XmlReader(httpcon));

您可能不应该使用 sun.misc.BASE64Encoder。而是在某个地方找到另一个。

来自：http ://cephas.net/blog/2005/02/09/retrieving-an-rss-feed-protected-by-basic-authentication-using-rome/

于 2012-09-24T19:08:25.680 回答
0

我发现这在身份验证方面更有弹性，这段代码在有和没有身份验证的情况下都适用：

URL feedUrl = new URL("http://the.url.to/the/feed");
//URL feedUrl = new URL("http://user:pass@the.url.to/the/feed");

HttpURLConnection connection = (HttpURLConnection) feedUrl.openConnection();
if (feedUrl.getUserInfo() != null) {
    String encoding = new sun.misc.BASE64Encoder().encode(feedUrl.getUserInfo().getBytes());
    connection.setRequestProperty("Authorization", "Basic " + encoding);
}

SyndFeedInput input = new SyndFeedInput();
SyndFeed feed = input.build(new XmlReader(connection));
于 2014-07-10T07:49:12.070 回答
0

您也可以使用以下内容代替

String encoding = new sun.misc.BASE64Encoder().encode("username:password".getBytes());

对此：

String BASIC_AUTH = "Basic " + Base64.encodeToString("username:password".getBytes(), Base64.NO_WRAP);
于 2014-09-03T08:52:21.647 回答