mysql - 从子查询 SQL 中选择最大数据，但它显示来自子查询的所有结果

Question

SELECT MAX( t.valuesum ) AS total, t.codebook
FROM (
    SELECT SUM( value ) AS valuesum, codebook
    FROM stock
    GROUP BY codebook
) t
GROUP BY t.codebook

在子查询中，输出为：

b001 35,
b002 20,
b0003 11

我只想看到：b001 35。请帮帮我。

Answer 1

第一种解决方案使用where条件：

SELECT t1.valuesum, t1.codebook
FROM (
        SELECT SUM( s.value ) AS valuesum, s.codebook
        FROM stock s
        GROUP BY s.codebook
     ) t1
WHERE t1.valuesum in (SELECT MAX( t2.valuesum ) AS total
                     FROM (
                             SELECT SUM( s2.value ) AS valuesum, s2.codebook
                             FROM stock s2
                             GROUP BY s2.codebook
                           )t2
                     ) 

SQL 小提琴演示

第二种解决方案使用having条件：

SELECT max(t1.valuesum), t1.codebook
FROM (
        SELECT SUM( s.value ) AS valuesum, s.codebook
        FROM stock s
        GROUP BY s.codebook
     ) t1
GROUP BY t1.codebook
HAVING max(t1.valuesum) = (SELECT MAX( t2.valuesum ) AS total
                     FROM (
                             SELECT SUM( s2.value ) AS valuesum, s2.codebook
                             FROM stock s2
                             GROUP BY s2.codebook
                           )t2
                     )

SQL 小提琴演示

Answer 2

试试这个

SELECT SUM( value ) AS valuesum, codebook 
FROM stock 
GROUP BY codebook
ORDER BY valuesum DESC
LIMIT 1

Answer 3

您可以通过单个查询简单地获取它 -

    SELECT MAX( t2.valuesum ) AS valuesum, t2.codebook
    FROM (
          SELECT SUM( s2.value ) AS valuesum, s2.codebook
          FROM stock s2
          GROUP BY s2.codebook
         )t2

演示：-http://sqlfiddle.com/#!9/ c2534 /15

Answer 4

试试这个

SELECT TOP 1 * FROM
(
  SELECT SUM([value]) AS valuesum, codebook
  FROM stock
  GROUP BY codebook
)
ORDER BY valuesum DESC

Answer 5

假设（根据评论和错误消息）您使用 MySQL：

SELECT SUM( value ) AS valuesum, codebook
FROM stock
GROUP BY codebook
ORDER BY valuesum DESC
  LIMIT 1 ;