0

这是我的代码。我不明白为什么我一直收到这个?

它应该递归地将基数从基数 10 更改为任何给定的基数。

任何帮助都是极好的。

 import java.util.Scanner;

 public class Recursion{

        public static void main(String[] args)
        {
                try {   System.out.println(" Please input the base you would like to convert into " );
                        Scanner BaseIn = new Scanner (System.in);
                        int base1 = BaseIn.nextInt();

                        System.out.println( "Now input the number you would like to convert" );
                        Scanner NumIn = new Scanner (System.in);
                        int number = NumIn.nextInt();

                        BaseConversion (number, base1);
                    }

                catch (Exception e)
                {
                System.out.print("somethigng stupid");
                }
        }

        public String BaseConversion(int num, int base)
        {
                if (num < base)
                {
                return new String ("" + num);
                }
                else
                {
                return BaseConversion (num/base, base) + new String("" + (num % base));
                }
        }

}
4

3 回答 3

1

您不能从静态上下文中进行非静态引用。您的上述代码甚至无法编译,因为您正试图从静态主方法调用非静态方法(BaseConversion)。

在创建 BaseConversion 方法后尝试运行您的代码static..

建议: - 请遵循编码约定,以使您的代码更有意义。您的方法和变量名称始终遵循驼峰式(以小写字母开头,随后的单词以大写字母开头)

于 2012-09-24T06:32:13.657 回答
0

您必须给出要运行的的名称,而不是方法的名称。

在这种情况下

java Recursion
于 2012-09-24T06:32:02.353 回答
0

BaseConversion是实例方法,您需要类的实例才能访问它。

所以你应该像这样调用它

`new Recursion().baseConversion(number, base1)` //I have changed name according to java conventions.

否则将其声明为static

您的课程将如下所示。你现在可以继续你的逻辑

public class Recursion {

public static void main(String[] args) {
    try {
        System.out
                .println(" Please input the base you would like to convert into ");
        Scanner BaseIn = new Scanner(System.in);
        int base1 = BaseIn.nextInt();

        System.out
                .println("Now input the number you would like to convert");
        Scanner NumIn = new Scanner(System.in);
        int number = NumIn.nextInt();

        System.out.println(new Recursion().baseConversion(number, base1));
    }

    catch (Exception e) {
        System.out.print("somethigng stupid");
    }
}

public String baseConversion(int num, int base) {
    if (num < base) {
        return new String("" + num);
    } else {
        return baseConversion(num / base, base)
                + new String("" + (num % base));
    }
}

}
于 2012-09-24T06:49:03.143 回答