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我在解析中有一个java bean类集值。我要求全局访问这个类，但是在使用它的实例静态并在其中赋值时给出空指针异常。代码如下：-

private String Responce;
private String Error;
private String Url;
private SIPModle objsip;
private VMModle objvmmodle;
private ArrayList<CustompadModle> objcmodlelist = new ArrayList<CustompadModle>();
private SettingModle objsettingmodle;
private WifiModle objwifimodle;

public String getResponce() {
    return Responce;
}
public void setResponce(String responce) {
    Responce = responce;
}
public String getError() {
    return Error;
}
public void setError(String error) {
    Error = error;
}
public ArrayList<CustompadModle> getObjcmodlelist() {
    return objcmodlelist;
}
public void setObjcmodlelist(CustompadModle objcmodlelist) {
    this.objcmodlelist.add(objcmodlelist);
}
public String getUrl() {
    return Url;
}
public void setUrl(String url) {
    Url = url;
}
public SIPModle getObjsip() {
    return objsip;
}
public void setObjsip(SIPModle objsip) {
    this.objsip = objsip;
}
public VMModle getObjvmmodle() {
    return objvmmodle;
}
public void setObjvmmodle(VMModle objvmmodle) {
    this.objvmmodle = objvmmodle;
}

public SettingModle getObjsettingmodle() {
    return objsettingmodle;
}
public void setObjsettingmodle(SettingModle objsettingmodle) {
    this.objsettingmodle = objsettingmodle;
}
public WifiModle getObjwifimodle() {
    return objwifimodle;
}
public void setObjwifimodle(WifiModle objwifimodle) {
    this.objwifimodle = objwifimodle;
}

我的要求是全局访问这个bean类。任何人都建议我

我在 doinbackground 中获取此对象并在该类的静态对象中分配为：AsyncTask {

    ProgressDialog objprogress = new ProgressDialog(
            UserSettingConfiguration.this);
    ApplicationRequestHandler objhandler = new ApplicationRequestHandler();

    @Override
    protected void onPreExecute() {
        this.objprogress.setMessage("Please Wait While Loading...");
        this.objprogress.isShowing();
    }

    @Override
    protected ConfigurationSttingModle doInBackground(String... params) {
        objconfigsetting = objhandler.getConfigurationSetting(params[0],
                params[1], params[2], params[3]);
        return objconfigsetting;
    }

    @Override
    protected void onPostExecute(ConfigurationSttingModle result) {
        if (this.objprogress.isShowing()) {
            this.objprogress.dismiss();
        }


    }
}

并在高级课程中使用；-

private static HashMap<String, String> SUMMARIES = new HashMap<String, String>() {

    private static final long serialVersionUID = 3055562364235868653L;

    {
        String server = UserSettingConfiguration.objconfigsetting.getObjsip().getServer();
        String displayname1 = UserSettingConfiguration.objconfigsetting.getObjsip().getUser();
        String user = UserSettingConfiguration.objconfigsetting.getObjsip().getUser();
        String password= UserSettingConfiguration.objconfigsetting.getObjsip().getPassword();

        put(FIELD_DISPLAY_NAME,displayname1);// "90901");
        put(FIELD_CALLER_ID,displayname1); //"90901");
        put(FIELD_SERVER,server);
        put(FIELD_USERNAME,user);
        put(FIELD_AUTH_ID, "207");
        put(FIELD_PASSWORD,password);
        put(FIELD_PROXY, null);
    }
};
4

1 回答 1

1

我认为单例模式将符合您的要求。

您必须添加以下代码：

private static MyJavaBeanClass = null;

public static MyJavaBeanClass getInstance(){
  if(null == instance){
    instance = new MyJavaBeanClass();
  }
  return instance;
}

您必须将 MyJavaBeanClass 更改为您的类的名称，然后您可以像这样在任何地方调用它：

MyJavaBeanClass.getInstance().setError("Testing");
于 2012-09-23T15:56:04.997 回答